Question

Solve the logarithmic equationD%28x%20%2B%206%29%20%20%3D%201" id="TexFormula1" title=" log_{3} {x}^{2} - log_{3}(x + 6) = 1" alt=" log_{3} {x}^{2} - log_{3}(x + 6) = 1" align="absmiddle" class="latex-formula">
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Answer 1

Answer:

Step-by-step explanation:

1 = base 3log3

substitute

logx^2-log(x+6) = log3

logx^2 - log(x+6) - log3 = 0

log( (x^2/(x+6))/3 ) = 0

anti-log

x^2/3(x+6) = 1

x^2 = 3(x+6)

x^2-3x-18=0

x=6 n -3

anti-log base 3 on both sides:

Answer 2

Answer:

Step-by-step explanation:

Using log(x) - log(y) = log (x/y)

logx^2 - log(x+6) = 1 is equal to:

log (x^2/(x+6)) = 1

Taking inverse base 3 log on both side:

x^2/(x+6) = 3

x^2 = 3x + 18

x^2 - 3x - 18 = 0

(x-6)(x+3) = 0

x = 6 or -3