Please help idk how to find the surface area of this triangular prism

Mathematics

2 answers:

Olin [163]3 years ago

7 0

1/2 bxh - b = base h = height

so 8cm (height) × 26cm (base) × 12cm (also base) = something something × 1/2 = answer...or ÷ 1/2 I forgot but its something like that I think. bruh just ask whoever's in the house lol

ra1l [238]3 years ago

5 0

Answer:

you have to find the area of the rectangle at the bottom and then find the area of the 2 long triangles and the 2 small triangles and add them together

Step-by-step explanation:

You might be interested in

REALLY NEED AN ALGEBRA 1 GENIUS RIGHT NOW!

Archy [21]

are the answers pictures????

6 0

3 years ago

What is 69/25 as a terminating decimal

Dennis_Churaev [7]

69/25 = 276/100 = 2.76

7 0

3 years ago

an underground mine elevator reaches a total depth of 99 meters. it descends 17% of the total distance every minute. how many me

malfutka [58]

17% of 99 is 16.83. Since that's only the distance it goes in one minute we have to multiply that by 3. 16.83 × 3 = 50.49. Since the elevator is moving down then it will be negative. The answer will be -50.49 meters.

4 0

3 years ago

Read 2 more answers

the work in an office take 150 hours to complete every week each person in the office works for 32 hours a week what is the smal

Lynna [10]

Answer:

5 people

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the equation of a line parallel to y=1/2×+6 that passes through (-4,1)

IgorC [24]

keeping in mind that parallel lines have exactly the same slope, let's check for the slope of the equation above

$y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{1}{2}}x+6\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}$

so we're really looking for the equation of a line whose slope is 1/2 and passes through (-4 , 1)

$(\stackrel{x_1}{-4}~,~\stackrel{y_1}{1})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{1}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{1}=\stackrel{m}{ \cfrac{1}{2}}(x-\stackrel{x_1}{(-4)}) \\\\\\ y-1=\cfrac{1}{2}(x+4)\implies y-1=\cfrac{1}{2}x+2\implies y=\cfrac{1}{2}x+3$

5 0

2 years ago