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Vika [28.1K]
3 years ago
8

At 50, Brian sets up an IRA, where he plans to deposit $12,000 at the end of each year until age 75. Find the amount of the annu

ity if he invests in a stock fund that yields 4% compounded annually.
Mathematics
1 answer:
kozerog [31]3 years ago
3 0

Answer: the amount of the annuity is $501000

Step-by-step explanation:

We would apply the future value which is expressed as

FV = C × [{(1 + r)^n - 1}/r]

Where

C represents the yearly payments.

FV represents the amount of money

in your account at the end of 25 years.

r represents the annual rate.

n represents number of years or period.

From the information given,

r = 4% = 4/100 = 0.04

C = $12000

n = 75 - 50 = 25

Therefore,

FV = 12000 × [{(1 + 0.04)^25 - 1}/0.04]

FV = 12000 × [{2.67 - 1}/0.04]

FV = 12000 × 41.75

FV = $501000

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Step-by-step explanation:

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Given that 'n' is a natural number. Prove that the equation below is true using mathematical induction.
LenaWriter [7]

<h3>To ProvE :- </h3>

  • 1 + 3 + 5 + ..... + (2n - 1) = n²

<u>Method</u><u> </u><u>:</u><u>-</u>

If P(n) is a statement such that ,

  1. P(n) is true for n = 1
  2. P(n) is true for n = k + 1 , when it's true for n = k ( k is a natural number ) , then the statement is true for all natural numbers .

\sf\to \textsf{ Let P(n) :  1 + 3 + 5 + $\dots$ +(2n-1) = n$^{\sf 2}$ }

Step 1 : <u>Put </u><u>n </u><u>=</u><u> </u><u>1</u><u> </u><u>:</u><u>-</u><u> </u>

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Step 2 : <u>Assume </u><u>that </u><u>P(</u><u>n)</u><u> </u><u>is </u><u>true </u><u>for </u><u>n </u><u>=</u><u> </u><u>k </u><u>:</u><u>-</u>

\sf\longrightarrow 1 + 3 + 5 + \dots + (2k - 1 ) = k^2

  • Add (2k +1) to both sides .

\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+1)=k^2+(2k+1)

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\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+1) + 1 -1  = (k +1)^2 \\

\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+(2k+2) - 1 = (k +1)^2

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\sf\longrightarrow 1 + 3+5+\dots+(2k-1)+\{2(k+1)-1\}= (k +1)^2

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<u>1.</u>(25)^{2t}

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