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iren [92.7K]
2 years ago
8

Find Equivalent Expression 1/2 (4x + 4)

Mathematics
1 answer:
Marrrta [24]2 years ago
8 0

Answer:

2x+2

Step-by-step explanation:

1/2(4x)+1/2(4)=2x+2

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I need the answer ASAP
iVinArrow [24]

Answer:

5

Step-by-step explanation:

When squaring the number 5 (i.e 5^2 ) the answer is 25. 5^{2} is the same thing as 5 times 5. Basically with the square root, you are going backwards, so you are therefore finding the base of it all.

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Two friends share 1/3 of a pitcher of
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⅙ pitcher

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2 years ago
How many solutions are there to the equation below |x|=77?
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C.

Solve for x by simplifying both sides of the equation, then isolating the variable.

x = 77, -77

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In 1626, the Dutch bought Manhattan Island, now part of New York City, for $24 worth of merchandise. Suppose that, instead, $24
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2008 - 1626 -= 382

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3 years ago
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A crawling tractor sprinkler is located as pictured below, 100 feet South of a sidewalk. Once the water is turned on, the sprink
deff fn [24]

Answer:

  a) see below

  b) 32 minutes after turn-on

  c) 52 minutes after turn-on

  d) 20 minutes

  e) 6856.6 ft²

Step-by-step explanation:

a) We have elected to put the origin at the point where the hose crosses the south edge of the sidewalk. Units are feet. Then the sprinkler starts at (0, -100). After 1 hour, 3600 seconds, the sprinkler is 1800 inches, or 150 ft north of where it started, so stops at (0, 50).

The lines forming the sidewalk boundaries are y=0 and y=10.

__

b) Water will first strike the sidewalk when the sprinkler is 20 feet south of it, or 80 feet north of where it started. The sprinkler travels that distance in ...

  (80 ft)(12 in/ft)/(1/2 in/s)(1 min/(60 s)) = 32 min . . . time to start sprinkling sidewalk

__

c) The sprinkler has to travel to a point 130 ft north of its starting position for the water to fall north of the sidewalk. That distance is traveled in ...

  (130 ft)(2/5 min/ft) = 52 min . . . time until end of sprinkling sidewalk

Note that we have combined the scale factors in the expression of part b into one scale factor of (2/5 min/ft).

__

d) The difference of times in parts b and c is the time water falls on the sidewalk: 20 minutes.

__

e) In one hour, the sprinkler travels a distance of ...

  (60 min)(5/2 ft/min) = 150 ft

Of that distance, 10 feet is sidewalk. So, the sprinkler covers an area of grass that is a 140 ft by 40 ft rectangle and a circle of 20 ft radius. The total area of that is ...

  A = LW + πr² = (140 ft)(40 ft) +π(20 ft)² = (14+π)(400) ft² ≈ 6856.6 ft²

The area of grass watered in 1 hour is about 6856.6 ft².

5 0
3 years ago
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