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seraphim [82]
3 years ago
12

A rectangle has a perimeter of 23 cm. Its area is 33 cm2. Determine the

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
5 0

Answer:

length = 6 cm; width = 5.5 cm

Step-by-step explanation:

Let the length = x. Let the width = y.

We use the formulas for area and perimeter using x and y, and the given values.

area = length * width

perimeter = 2(length + width)

xy = 33

2(x + y) = 23

Solve the first equation for x:

x = 33/y

Substitute 33/y for x in the second equation.

2(33/y + y) = 23

66/y + 2y = 23

Mulrtiply both sides by y.

66 + 2y^2 = 23y

2y^2 - 23y + 66 = 0

(2y - 11)(y - 6) = 0

2y - 11 = 0   or   y - 6 = 0

y = 11/2 = 5.5   or   y = 6

xy = 33

x * 11/2 = 33

x = 33 * 2/11

x = 6

Answer: length = 6 cm; width = 5.5 cm

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Step-by-step explanation:

AB=28 !... .......hope this helps..

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3 years ago
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20 points
Lubov Fominskaja [6]

Answer:

1/3

Step-by-step explanation:

Slope = ( y₂ - y₁ ) ÷ ( x₂ - x₁ )

y₂ = 9

y₁ = 7

x₂ = 4

x₁ = -2

y₂ - y₁ = 9 - 7 = 2

x₂ - x₁ = 4 - -2 = 6

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3 0
3 years ago
Given:
diamong [38]

Answer:

10-5\sqrt{2}

Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

Also,

\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

So, radius of circle = 10-5\sqrt2

8 0
3 years ago
Can y’all help me on question 13?!
Doss [256]

Answer:

90 cm²

Step-by-step explanation:

The shape can be divided in three rectangles.

Area = area of rectangle 1 + area of rectangle 2 + area of rectangle 3

✔️Area of rectangle 1 = L*W

L = 5 cm

W = 3 cm

Area = 5*3 = 15 cm²

✔️Area of rectangle 2 = L*W

L = 6 + 5 + 1 = 12 cm

W = 5 cm

Area = 12*5 = 60 cm²

✔️Area of rectangle 3 = L*W

L = 5 cm

W = 3 cm

Area = 5*3 = 15 cm²

✅Area of the shape = 15 + 60 + 15 = 90 cm²

4 0
2 years ago
Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(2,−3) B(4,−3) C(4,5) D(2,5
AveGali [126]

Answer:

21 unit square

Step-by-step explanation:

First you want to find the length and width of the rectangle using the distance formula:

d=√(x2-x1)²+(y2-y1)²

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AB=√3² + 0

AB=√9

AB=3

BC=√(6-6)²+ (5 - -2)²

BC=√0 + 7²

BC=√49

BC=7

We can find the area by multiplying these two distances together:

A=(3)(7)

A=21 units square.

Hope it helped...... And plz mark BRAINLIEST

Tysm

7 0
3 years ago
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