Answer:
ΔCFG is an isosceles triangle.
Step-by-step explanation:
From the picture attached,
From ΔABF and ΔEDG,
Conditions for ΔABF and ΔEDG by SSS property of congruence,
1). AB ≅ DE [Given]
2). (BC + CF) = (DF + CG)
CF = CG [Given → BC = DF]
3). FA ≅ EG
(AG + GF) ≅ (EF + GF)
AG ≅ EF
Since, two sides of ΔCFG are equal in measure
ΔCFG is an isosceles triangle.