Theorem of Pythagoras: a²+b²=c², where a, b is legs and c is hypotenuse.
We've got one leg known, let it be a=sqrt 3,
and the hypotenuse - c=2sqrt3
Putting these into the theorem, we get an equation: (sqrt3)²+b²=(2sqrt3)² . Solving it, we get:
3+b²=4*3
3+b²=12
b²=9
This equation has two possible roots: b=3 and b=-3. Since this is a triangle, there can't be a side with a negative value => b=3.
The answer is a. 3
Answer:
B (4,2)
Step-by-step explanation:
This coordinate pair would make the relation not a function because there would be two X values that are the same.
6i^4 = 6*1 = 6
6i^3 = 6*(-i) = -6i
-2i^2 = (-2)*(-1) = 2
sqrt(-49) = 7i
So, we have: 6 - 6i + 2 + 7i = 8 + i
The answer is D
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Answer:
3. x = 1<x−2<71<x-2<7
9<x+7<109<x+7<10
7<x+4<12
5. x = 1<x−2<71<x-2<7
9<x+7<109<x+7<10
7<x+4<12
Step-by-step explanation:
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