Answer:
It is a reflection of the y axis, with 2 units down. :)
Step-by-step explanation:
Answer:
B. No, this distribution does not appear to be normal
Step-by-step explanation:
Hello!
To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.
The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.
As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.
The answer is B.
I hope it helps!
Wen you deduct an amount from something
Answer:
1.
a = 112
b = 68
c = 68
2.
a = 127
3.
a=35
b=40
c=35
d=70
4.
a= 30
b=70
c = 30
d=70
e = 130
I'll help you with the rest later
Step-by-step explanation:
a = 112 because of allied angles rule
b and c = 68 because of angles at a point
360-112-112 ÷2
2. a = 127 because of angles on a straight line rule.
180-38-15
3. d= 70, vertically opposite angle
using angles on a straight line, 180 - 70 - 40 ÷ 2
we now have the two angles and because they are vertically opposite a and c = 35
b = 40 because of vertically opposite angles
4. a=30 because 90-70
since a=30, take 90 - 30 to get b, 70
d= 70, vertically opposite angles
e = 130 because a+b+c, vertically opposite angles