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Firlakuza [10]
3 years ago
6

22. What is the importance of cilia and flagella for microorganisms?

Biology
2 answers:
neonofarm [45]3 years ago
8 0
Motile cilia use their rhythmic undulation to sweep away substances, as in clearing dirt, dust, micro-organisms and mucus, to prevent disease.
Irina-Kira [14]3 years ago
3 0

Answer:

<h2>Cilia and flagella are motile cellular appendages found in most microorganisms and animals, but not in higher plants. In multicellular organisms, cilia function to move a cell or group of cells or to help transport fluid or materials past them.Cilia and flagella are organelles on cells that provide propulsion, sensory devices, clearance mechanisms and numerous other important functions in living organisms.</h2>

Explanation:

<h2><em><u>PLEASE</u></em><em><u> MARK</u></em><em><u> ME</u></em><em><u> BRAINLIEST</u></em><em><u> AND</u></em><em><u> FOLLOW</u></em><em><u> ME</u></em><em><u> LOTS</u></em><em><u> OF</u></em><em><u> LOVE</u></em><em><u> FROM</u></em><em><u> MY</u></em><em><u> HEART</u></em><em><u> AND</u></em><em><u> SOUL</u></em><em><u> DARLING</u></em><em><u> TEJASWINI</u></em><em><u> SINHA</u></em><em><u> HERE</u></em><em><u> ❤️</u></em></h2>
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Describe how polyploidy is used in the field of agriculture.
Arisa [49]

polyploidy plants are sterile, usually completely seedless, but may have vestiges of seeds (like the kind of bananas we eat do). Polyploidy plants also usually produce much larger plants than their aneuploidy counterparts do. Bigger fruits are more marketable than smaller ones.

Source from: https://answers.yahoo.com/question/index?qid=20100117182433AAx7K1t

5 0
3 years ago
Read 2 more answers
pThe probability of having an offspring with both the dominant phenotypes for both genes is equal to the product of the individu
Elena-2011 [213]

The product probability rule states P(A∩B) = P(A) x P(B). In the exposed example, the probability of having a dominant phenotype is 9/16.

<h3>What is the product probability rule?</h3>

The product probability rule allows us to calculate the probability of occurrence of event A and event B at the same time.

It is about a joint probability of two or more events that might happen simultaneously, not excluding each other.

This rule is based on the dependence or independence of the events. If two events A and B are independent of each other, the occurrence of one of them does not affect the occurrence of the other one.

For independent events, the rule establishes that, given two different events A and B, the probability of occurrence of both together is

P(A∩B) = P(A) x P(B)

The probability of inheriting one of the alleles from each parent is 0.5 (beacause each parent has two alleles).

According to this, the probability of having a dominant phenotype for both traits depends on the paretal genotypes.

For instance, let us analyze the cross between two dihybrid individuals AaBb  x  AaBb.

Assuming the involved genes code for different traits and both are independent genes, for easier calculations, we can perform crosses that involve each of the genes separately -events-, and then multiply de results according to the genotype and phenotype we are interested in (A-B-)

<u>Gene A</u>

Parentals) Aa   x   Aa

Gametes) A   a     A   a

Punnett square)       A(1/2)      a(1/2)

                    A(1/2)    AA(1/4)     Aa(1/4)

                    a(1/2)     Aa(1/4)      aa(1/4)

F1) Genotype

      <u>1/4 AA</u> ⇒ 1/2A x 1/2A

      2/4 = 1/2 Aa ⇒ (1/2A x 1/2a) + (1/2A x 1/2a)

      1/4 aa ⇒ 1/2a x 1/2a

      Phenotype

     <u> 3/4 A-</u> ⇒ 1/4AA + 2/4Aa

      1/2 aa

     

<u>Gene B</u>

Parentals) Bb   x   Bb

Gametes) B   b     B    b

Punnett square)   B      b

                   B       BB    Bb

                    b       Bb   bb

F1 Genotype

      <u>1/4 BB</u> ⇒ 1/2B x 1/2B

      2/4 = 1/2 Bb ⇒ (1/2B x 1/2b) + (1/2B x 1/2b)

      1/4 bb ⇒ 1/2b x 1/2b

      Phenotype

     <u> 3/4 B-</u> ⇒ 1/4 BB + 2/4 Bb

      1/2 bb

The probability of having a dominant genotype and phenotype for both traits is,

  • Genotpe AABB ⇒ 1/4 AA x 1/4 BB = <u>1/16 AABB</u>
  • Phenotype A-B- ⇒ 3/4 A-  x  3/4 B- = <u>9/16 A-B-</u>

<u />

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You can learn more about the product probability rule in crosses at

brainly.com/question/13049972

brainly.com/question/14933381

4 0
3 years ago
(18pts)
den301095 [7]

The answer is C)Resistant bacteria cannot be attacked by penicillin

4 0
4 years ago
Which question can be tested scientifically?
konstantin123 [22]
Does humidity affect the decay rate of leaves?
4 0
2 years ago
You perform an experiment in which you take 16 pots of strawberry plants and give half of them 1 gm of ammonium nitrate per lite
alexandr1967 [171]

Answer:

Height of the plants

Explanation:

Dependent variable is the effect that is being measured in an experiment while independent variable is the cause of that effect. Hence, dependent variable is not controlled or changed.  

According to this question, height of the plants is the effect of the amount of ammonium nitrate and light. Hence, it defines the output or end result of the variation that is being studied.

5 0
3 years ago
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