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3 years ago

(HELP ME ASAP PLEASE ILL GIVE BRAINLIEST!!)

Mathematics

1 answer:

gulaghasi [49]3 years ago

4 0

Sugar sweet 7500 is a lot of money you got there
Explanation

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What are the relative frequencies, to the nearest hundredth, of the rows of the two way table?

Nookie1986 [14]

Answer: A B

Group A 0.25 0.75

Group B 0.45 0.55

Step-by-step explanation:

Since we have given that

Number of people of A in Group A = 15

Number of people of B in Group A = 45

Number of people of A in Group B = 20

Number of people of B in Group B = 25

Total number of people in Group A = 15+45 = 60

Total number of people in Group B = 20+25 = 45

So, Relative frequencies will be given below:

Relative frequency of A in Group A is given by

$\frac{15}{60}=0.25$

Relative frequency of B in Group A is given by

$\frac{45}{60}=0.75$

Relative frequency of A in Group B is given by

$\frac{20}{45}=0.45$

Relative frequency of B in Group B is given by

$\frac{25}{45}=0.55$

Hence, A B

Group A 0.25 0.75

Group B 0.45 0.55

5 0

4 years ago

If someone can plsssssss help

lara [203]

The formula you are looking for is t = 1.29 x k

Hope this helps your test. :)

4 0

3 years ago

Write 56 1/4% as a fraction is simplest form

bazaltina [42]

56.25% as a decimal is 0.5625

0.5626 is equal to 5625/10000, which can be simplified to 9/16

This is because the common factor of 5625 and 10000 is 625. We divide the numerator and denominator by 625 to achieve 9/16.

8 0

4 years ago

Arrange the numbers in increasing order.

SVEN [57.7K]

Answer:14.200,14.204,14.210,14.240

Step-by-step explanation:

8 0

3 years ago

Find the general solution to the differential equation modeling how a person learns:

Luda [366]

Here we want to solve differential equations, we will see that the general solution is:

$y = A*e^{-t} + 100$

We want to solve the differential equation:

$\frac{dy}{dt} = 100 - y$

From this is pretty clear that y is an exponential function, with an exponent of -1*t.

We can write it generally as:

$y = A*e^{-t} + B\\\\\frac{dy}{dt} = -A*e^{-t}$

Then if we set B = 100 we get:

$y = A*e^{-t} + 100\\\\\frac{dy}{dt} = -A*e^{-t} \\\\\frac{dy}{dt} = -A*e^{-t} - 100 + 100 = -y + 100$

So we just found the general form of the function.

Now we have two cases:

A) y(0) = 35

$y(0) = A*e^{-0} + 100 = 35\\= A + 100 = 35\\\\A = 35 - 100 = -65$

In this case, the function is:

$y = -65*e^{-t} + 100$

B) y(0) = 125

$125 = A*e^0 + 100\\\\\125 - 100 = A\\\\25 = A$

In this case, the function is:

$y = 25*e^{-t} + 100$

Now we want to see which one of the two can represent how a person learns. Just look at the graph below:

The green line is the one for y(0) = 35, and the blue one is for y(0) = 125.

Notice that for small values of t, the blue function is really large, thus it can't really model how a person learns (is larger for smaller values of t than for larger values).

So y(0) = 35 represents better how a <em>person can learn</em> (but not exactly, because you can see that it eventually becomes almost constant, which is something that really does not happen) so the correct option is <u>D: none of the above.</u>

If you want to learn more, you can read:

brainly.com/question/353770

3 0

3 years ago