The width of his office on the floor plan is 2.5 in.
Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;

Seperate the differential equation and solve for the constant C.

You have 100 rodents when:

You have 1000 rodents when:

H(-10)=70
because when you input -10 in for each a, it will equal 70
1(Identifying):
Tomatoes-x--$3 per lb
Mushrooms- 1/3 x-- $10 per lb
Peaches- x+1-- $6 per lb
2(Equation):
3x+6(x+1)+1/3x*10=80
3x+6x+6+10/3 x=80
12 1/3 x= 74
x=74÷(12+1/3)
Step 3(Final Equations):
74*3/37=6=tomatoes
Meaning...
6+1=7=Peaches
6/3=2= mushrooms
Answer:
7 lb of peaches, 6 lb of tomatoes, and 2 lb of mushrooms