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Effectus [21]
3 years ago
13

What is the equation of the line, in point slope form, that passes through the points (-7,10) and (-6,8)

Mathematics
1 answer:
melomori [17]3 years ago
5 0

\displaystyle\bf\\The~points~is~(-7,~10)~and~(-6.~8)\\\\m=\frac{y2-y1}{x2-x1}\\\\\\m=\frac{8-10}{-6-(-7)}\\\\\\m=\frac{-2}{-6+7}\\\\\\m=\frac{-2}{1}\\\\\\\boxed{\bf~m=-2}

 

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Step-by-step explanation:

<u>1 step:</u> Difference in brackets

3.5-2\dfrac{1}{3}=3\dfrac{1}{2}-2\dfrac{1}{3}=(3-2)+\left(\dfrac{1}{2}-\dfrac{1}{3}\right)=1+\dfrac{3-2}{3\cdot 2}=1+\dfrac{1}{6}=1\dfrac{1}{6}

<u>2 step:</u> 0.75\div\dfrac{1}{3}

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<u>4 step:</u>

2\dfrac{1}{4}\times 1\dfrac{1}{6}=\dfrac{2\cdot 4+1}{4}\times \dfrac{1\cdot 6+1}{6}=\dfrac{9}{4}\times \dfrac{7}{6}=\dfrac{63}{24}=\dfrac{21}{8}

<u>5 step:</u>

\dfrac{9}{4}+32-\dfrac{21}{8}+1.65=(32+1.65)+\left(\dfrac{9}{4}-\dfrac{21}{8}\right)=33.65+\dfrac{9\cdot 2-21}{8}=33.65-\dfrac{3}{8}=33.65-0.375=33.275

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