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3 years ago

I need help completing this problem ASAP

Mathematics

1 answer:

aalyn [17]3 years ago

5 0

4/(√x - √(x - 2)) × (√x + √(x - 2))/(√x + √(x - 2))

= 4 (√x + √(x - 2)) / ((√x)² - (√(x - 2))²)

= 4 (√x + √(x - 2)) / (x - (x - 2))

= 4 (√x + √(x - 2)) / (x - x + 2)

= 4 (√x + √(x - 2)) / 2

= 2 (√x + √(x - 2))

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Plz help with this word problem

Andreyy89

He will mix some 20% solution and some 70% solution to make 60% solution.

Let x = number of liters of 20% solution.
Let y = number of liters of 70% solution.

He wants to make 50 liters of 60% solution, so

x + y = 50   First Equation

The amount of acid in x amount of 20% solution is 20% of x, or 0.2x
The amount of acid in y amount of 70% solution is 70% of y, or 0.7y
The amount of acid in 50 liters of 60% solution is 60% of 50 liters, or 0.6 * 50 = 30
Now we add the amounts of acid.
0.2x + 0.7y = 30   Second Equation

x + y = 50
0.2x + 0.7y = 30

-0.2x - 0.2y = -10
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y = 40

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Answer: He needs 10 liters of 20% solution and 40 liters of 70% solution.

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(x+2y = 10 16y=-3x+30

Harlamova29_29 [7]

Answer:

x = 10, y = 0

Step-by-step explanation:

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