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3 years ago

I need help completing this problem ASAP

Mathematics

1 answer:

aalyn [17]3 years ago

5 0

4/(√x - √(x - 2)) × (√x + √(x - 2))/(√x + √(x - 2))

= 4 (√x + √(x - 2)) / ((√x)² - (√(x - 2))²)

= 4 (√x + √(x - 2)) / (x - (x - 2))

= 4 (√x + √(x - 2)) / (x - x + 2)

= 4 (√x + √(x - 2)) / 2

= 2 (√x + √(x - 2))

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What are the roots of x in -10x^2 + 12x − 9 = 0

taurus [48]

Answer:

No roots

Step-by-step explanation:

the discriminant Δ = 12²-4×(-10)×(-9) = -216

since ∆ is negative then the equation -10x^2 + 12x − 9 = 0 has no solution .

8 0

3 years ago

The average weight of 7 potted plants is 23 pounds. An 8th potted plant is added to the pallet,

cluponka [151]

Answer:

The weight of the 8th plant is 39lb

Step-by-step explanation:

Given:

Average Weight of 7 plants = 23lb

Average Weight of 8 plants = 25lb

Required:

Weight of the 8th plant

To solve this, the total weight of the initial 7 plants need to be calculated;

$Average = \frac{Sum-of-weights}{Number-of-Plants}$

Substitute 23 for Average and 7 for Number of plants

$23 = \frac{Sum-of-weights}{7}$

Multiply both sides by 7

$7 * 23 = \frac{Sum-of-weights}{7} * 7$

$161 = Sum-of-weights$

Hence, the 7 plants weigh 161

Represent the weight of the 8th plant with E

When the 8th plant is added;

The sum of the weight becomes 161 + E

And the number of plants becomes 8

The average is calculated as thus

$Average = \frac{Sum-of-weights}{Number-of-Plants}$

$25 = \frac{161 + E}{8}$

Multiply both sides by 8

$8 * 25 = \frac{161 + E}{8} * 8$

$200 = 161 + E$

Subtract 161 from both sides

$200 -161 = 161 - 161 + E$

$39 = E$

Reorder

$E = 39$

Hence, the weight of the 8th plant is 39lb

6 0

3 years ago

Monica is 2 years older than Liam. Emmett is 34. Brittany is 5 years older than Emmett and 4 years older than Liam. How old is L

Andreas93 [3]

Answer:

She is 30

Explanation:

Because if you read it right it says "Emmett is 4 years older than Liam." Also you had a grammar error in it.

6 0

4 years ago

Consider the rectangle.

SCORPION-xisa [38]

Given:

The graph of a rectangle.

The given rectangle is dilated from the origin by a scale factor of 3.

To find:

The vertices of the image of the rectangle after the dilation.

Solution:

From the given graph it is clear that the vertices of the rectangle are A(0,2), B(0,4), C(3,4) and D(3,2).

If a figure is dilated from the origin by a scale factor of 3, then

$(x,y)\to (3x,3y)$

Using this rule, the vertices of the image are:

$A(0,2)\to A'(3(0),3(2))$

$A(0,2)\to A'(0,6)$

Similarly,

$B(0,4)\to B'(3(0),3(4))$

$B(0,4)\to B'(0,12)$

And,

$C(3,4)\to C'(3(3),3(4))$

$C(3,4)\to C'(9,12)$

And,

$D(3,2)\to D'(3(3),3(2))$

$D(3,2)\to D'(9,6)$

The vertices of the image after dilation are (0,6), (0,12), (9,12), (9,6).

Therefore, the correct options are B and F.

3 0

3 years ago

To apply frosting to a cake, a baker twists a plastic bag containing the frosting into a cone shape with a diameter of 4 in and

geniusboy [140]

Radius of cone = 4/2 = 2 in
height os cone = sqrt(6^2 - 2^2) = sqrt(36 - 4) = sqrt(32)
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6 0

3 years ago

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