3 years ago

How do I find the missing sides?

Mathematics

1 answer:

iVinArrow [24]3 years ago

7 0

Answer:

You would realize that this is a right triangle with angles of 45-45-90. This means that the sides are 1-3 root 2-2. Hope this helps!!

Step-by-step explanation:

You might be interested in

What is the distance between (-5, -5) and (-9, -2)?

OLEGan [10]

Answer:

4,3 difference

Step-by-step explanation:

|-5,-5|=5,5

|-9,-2|=9,2

9-5=4

5-2=3

4,3 difference

7 0

3 years ago

The graph of a 4th-degree polynomial is shown. How many real zeros does this function have?

Neporo4naja [7]

Answer:

C: 3

Step-by-step explanation:

The graph touches or crosses the x-axis in 3 places; thus, there are 3 real zeros.

6 0

3 years ago

Read 2 more answers

The dot plot shows how much hairdressers in Margot's area charge for a woman's haircut. The least expensive cut is $25. Margot d

r-ruslan [8.4K]

The correct answer is The center is at $36.

8 0

3 years ago

Read 2 more answers

mr.rogers is buying candy for his class. he'll distribute the candy equally among his 25 scholars, and he wants each scholar to

stellarik [79]

25 scholars × 3 candies = 75 candies

5 candies for himself = 80

Answer: 80 candies

3 0

4 years ago

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

3 years ago