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jolli1 [7]
2 years ago
6

Help pls I’m confused ‍♂️

Mathematics
2 answers:
Oliga [24]2 years ago
7 0

Answer:

I think a number sorry trying to get points for some reason I am out.

Step-by-step explanation:

wariber [46]2 years ago
4 0

L=41 + d

d = construction after 27 days

so L = 41 + (27*1)

as per question only a mile is constructed each day

L = 41+ 27

L = 68 miles total length of the road, after 27 days

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New York City is building an outdoor skating rink that is circular. If the diameter of the circle is 92 meters, what is the area
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Write an equation in point-slope form for the line through the given point with the given slope.
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In 2008, the average household debt service ratio for homeowners was 13.2. The household debt service ratio is the ratio of debt
ankoles [38]

Answer:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

df=n-1=44-1=43  

p_v =P(t_{(43)}>1.436)=0.079  

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

Step-by-step explanation:

Information given

\bar X=13.88 represent the sample mean

s=3.14 represent the sample standard deviation

n=44 sample size  

\mu_o =13.2 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to conduct a hypothesis in order to check if the true mean has increased from 2008 , and the system of hypothesi are:  

Null hypothesis:\mu \leq 13.2  

Alternative hypothesis:\mu > 13.2  

The statistic for this case is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculating the statistic

Replacing the info given we got:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

P-value

The degrees of freedom are:

df=n-1=44-1=43  

Since is a right tailed test the p value is:  

p_v =P(t_{(43)}>1.436)=0.079  

Decision

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

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3 years ago
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Annette [7]

Answer:

negative :)

Step-by-step explanation:

hope this helps

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