According to the question,
6x + 90 = -42
<h3>To Find:</h3>
The value of x.
<h3>Solution:</h3>
6x = -42 + 90
or, x = 48/6
or, x = 8
<h2>Answer:</h2>
The value of x is 8.
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B is the true answer. hope this helps
Answer:
The population of deer at any given time = 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Step-by-step explanation:
This is an example of logistic equation on population growth
carrying capacity, k = 200
Rate, r = 3% = 0.03
Initial Population, P1 = 80
P(t) =?
P(t) = (P1 (k)(e^rt)) ÷ (k- P1 + P1(e^rt))
P(t) = (80 (200)(e^0.03t)) ÷ (200 - 80 + 80(e^0.03t))
= (16000(e^0.03t)) ÷ (120 + 80(e^0.03t))
= 200(e^0.03t) ÷ (1.5 + (e^0.03t))
Answer:
Here, we have:
P(5 days snow in this 8 days) = 8C5 x (0.85)^5 x (1 - 0.85)^3 = 0.084
P(6 days snow in this 8 days) = 8C6 x (0.85)^6 x (1 - 0.85)^2 = 0.238
P(7 days snow in this 8 days) = 8C7 x (0.85)^7 x (1 - 0.85)^1 = 0.385
P(8 days snow in this 8 days) = 8C8 x (0.85)^8 x (1 - 0.85)^0 = 0.272
Add up those above, then the probability that it will snow AT LEAST five of those days in February:
P = 0.084+ 0.238 + 0. 385 + 0.272 = 0.979
Hope this helps!
:)
