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17 one point shots and 39 two point shots were made
Solution:
Given that,
At a basketball game, a team made 56 successful shots
They were a combination of 1- and 2-point shots
Let "x" be the number of 1 point shots
Then, 56 - x is the number of two point shots
The team scored 95 points in all
Therefore,
1(number of 1 point shots) + 2(number of two point shots) = 95
x + 2(56 - x) = 95
x + 112 - 2x = 95
x = 112 - 95
x = 17
Then, number of two point shots = 56 - x = 56 - 17 = 39
Thus 17 one point shots and 39 two point shots were made
The mean of the distribution of the sampling mean is the same as the mean of the population, 18.6.
Answer:
6305
StepStep-by-stepStepStep-by-step-by-step-by-step explanation:
multply
Answer:
III only
Step-by-step explanation:
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Answer:
1036 students
Step-by-step explanation:
Let the number of students at West High be "w" and the number of students at East High be "e"
West High population is 250 FEWER than TWICE of East High, we can write:
w = 2e - 250
Total students in both schools is 2858, so we can write 2nd equation as:
e + w = 2858
We can replace 1st equation in 2nd to get an equation in e, and find "e":
e + w = 2858
e + (2e - 250) = 2858
3e - 250 = 2858
3e = 2858 + 250
3e = 3108
e = 3108/3
e = 1036
Hence,
number of students attending East High School = 1036 students
