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Semenov [28]
3 years ago
6

Evaluate bc + 5a when a = 3, b = 4, and c = -6

Mathematics
2 answers:
BabaBlast [244]3 years ago
8 0
Evaluation by bc+5a when a is 3 and b is 4 and c is -6 it is 51
Rasek [7]3 years ago
3 0

Answer:

-15

Step-by-step explanation:

if b= 4 and c=-6 it would be 5 times -6 which equals to -30. since this equation needs to be done with pemdas you dont add just yet. then you go and multiply 5 times 3 which is 15. and then you can add both totals you got which would be 15 + -30.

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Find mDCAˆ. the question says that the angle is 3x+19 the smaller arc is 91 and the bigger is 17x-3 it is one of those problems
valina [46]

Answer: Option C.

Step-by-step explanation:

Let as consider the below figure is attached below.

We know that angle between tangent and secant is half of difference of major and minor arcs.

\angle ABC=\dfrac{arc(AD)-arc(AC)}{2}

3x+19=\dfrac{17x-3-91}{2}

Multiply both sides by 2.

6x+38=17x-94

38+94=17x-6x

132=11x

Divide both sides by 11.

12=x

The value of x is 12.

arc(AD)=17(12)-3

arc(AD)=204-3

arc(AD)=201^{\circ}

Now,

arc(DCA)=360^\circ-arc(AD)

arc(DCA)=360^\circ-201^{\circ}

m\widehat {DCA}=159^{\circ}

Therefore, the correct option is C .

5 0
3 years ago
NutritionCalc Plus uses the equations from the National Academy of Medicine to calculate the Estimated Energy Requirement (EER)
olga nikolaevna [1]

Answer:

The correct option is (A).

Step-by-step explanation:

The equation for the Estimated Energy Requirement (EER) of 19 or more years older men is:

EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)

Here,

AGE = age counted in years

PA = appropriate physical activity factor

WT = weight in kilograms

HT = height in meters

The physical activity factor for men and women is:

Activity Level       PA (men)      PA (Women)

Sedentary              1.00                1.00

    Low                    1.11                1.12

  Active                   1.25                1.27

Very Active              1.48                1.45

Given:

AGE = 22 year-old male college student

PA = low = 1.11

WT = 180 pounds = 81.6466 kg

HT = 5'10" = 1.778 m

Compute the value of EER as follows:

EER = 662 - (9.53 \times AGE) + PA \times (15.91 \times WT + 539 \times HT)

        = 662 - (9.53 \times 22) + 1.11 \times (15.91 \times 81.6466 + 539 \times 1.778)\\\\=662-209.66+1.11\times (1298.997406+958.342)\\\\=452.34+2505.64674066\\\\=2957.98674066\\\\\approx 2962

Thus, the EER for a 22-year-old male college student is approximately 2962 kcal.

The correct option is (A).

6 0
3 years ago
The cost split among 4 people
vlada-n [284]

Answer:1 dollar each

Step-by-step explanation:

3 0
4 years ago
12. Solve the following equation: 6y - 20 = 2y - 4.
Tju [1.3M]

Answer:

option C   y=4

Step-by-step explanation:

we have:

6y - 20 = 2y - 4.

6y-2y=20-4

4y=16

y=16/4

y=4

8 0
3 years ago
Read 2 more answers
1 point
jek_recluse [69]

Answer:

I think It's option C

Step-by-step explanation:

But I am not sure It's correct or not

I hope It's helpful

3 0
3 years ago
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