Given:
baked: 6 <span>cookies and 4 brownies
can bake 25 more either </span><span>cookies or brownies
</span><span>Let x represent the number of more cookies that Midge can bake
Let y represent the number of more brownies that Midge can bake.
cookies = 6 + x
brownies = 4 + y
(6 + x) + (4 +y) </span>≤ 25
10 + x + y ≤ 25
x + y ≤ 25 - 10
x + y ≤<span> 15
y </span>≤ <span>15 - x
</span><span>The following graphs best represents the relationship between x and y is:
</span>
<span>line joining ordered pair 0, 15 and 7, 8 and the region below this line which lies in the first quadrant is shaded</span><span>
</span>
Answer:
Your answer would be D, the last one
<em>a = 17</em>
<em>b = 18</em>
<em>c = 19</em>
- <em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em>a + b + c = 54</em>
<em>b = a + 1</em>
<em>c = a + 2</em>
<em>replace b ; c</em>
<em>a + (a + 1) + (a + 2) = 54</em>
<em>3a = 54 - 3</em>
<em>3a = 51</em>
<em>a = 51 : 3</em>
<em>a = 17</em>
<em>b = 18</em>
<em>c = 19</em>
<em>Good luck !</em>
The work required to stretch the spring is 350J.
<h3>Hooke's Law</h3>
This law can be written by the formula: F=kx, where:
F= elastic force (N)
k= spring constant (N/m)
x= linear displacement (m)
<h3>Spring Work</h3>
For finding the spring work in J, you should apply the formula
, where:
W= work (J)
k= spring constant (N/m)
x= difference between the linear displacements (m)
The question gives:
x=5 cm=0.05m requires a force of 1.4N
x=8 cm =0.08m
- Step 1 - First, you should find the spring constant from Hooke's law, for x=5 cm and F=1.4N.

- Step 2 - Now you can apply the formula for spring work.

Read more about the spring work here:
brainly.com/question/3317535
Answer:
3 and -3
Step-by-step explanation: