2 years ago

Complete the statement: The quotient___when the divisor is doubled.

Mathematics

1 answer:

KengaRu [80]2 years ago

4 0

The quotient is halved when the divisor is doubled.

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X-y=3 X+2y=-6 Solve using substitution

Tresset [83]

X-y=3=>x=3+y
X+2y=-6
=========
3+y+2y=-6
3+3y=-6
3y=-6-3
3y=-9
y=-3

X+2y=-6
X+2(-3)=-6
X-6=-6
X=0

3 0

2 years ago

Solve the proportion using equivalent ratios. Explain the steps you used to solve the proportion, and include the answer in your

NikAS [45]

10x=60
x=6
10/3=20/6
^^^^^^^^^^^^

7 0

2 years ago

Read 2 more answers

1 Looking at the angle relationship below, what is the value of x? 1 . 45°

Andre45 [30]

Answer:

Step-by-step explanation:

They add up to 90, so 90 - 45 = 45 degrees

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2 years ago

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Sloan [31]

Answer:

Sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$ is $\mathbf{\frac{9x-4}{x^2-4}}$

Option B is correct answer.

Step-by-step explanation:

We need to find sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$

Finding sum of $\frac{7}{x^2-4}$ and $\frac{2}{x+2}$ :

$\frac{7x}{x^2-4}+\frac{2}{x+2}$

We know that $x^2-4 =(x+2)(x-2)$

Replacing x^2-4

$\frac{7x}{(x+2)(x-2)}+\frac{2}{x+2}$

Now, taking LCM of (x+2)(x-2) and (x+2) we get (x+2)(x-2)

$=\frac{7x+2(x-2)}{(x+2)(x-2)}\\=\frac{7x+2x-4}{(x+2)(x-2)}\\=\frac{9x-4}{(x+2)(x-2)}\\=\frac{9x-4}{x^2-4}$

So, Sum of $\frac{7x}{x^2-4}$ and $\frac{2}{x+2}$ is $\mathbf{\frac{9x-4}{x^2-4}}$

Option B is correct answer.

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2 years ago

Linear Inequalities & Systems of Inequalities

Rudik [331]

Answer:

use M A T H W A Y

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3 years ago