Given that the First term of the Arithmetic sequence = -3
⇒ a = -3
We know that nth term of a Arithmetic sequence is : Tn = a + (n - 1)d
where a is the first term and d is the common difference
Given that 10th term is 15
⇒ T₁₀ = -3 + (10 - 1)d
⇒ -3 + (10 - 1)d = 15
⇒ 9d = 18
⇒ d = 2
⇒ Common difference of given Arithmetic Sequence is 2
Answer:
D. 18.9 ÷ 9
Step-by-step explanation:
we need to divide
1.89 ÷ 0.9 but write it in different form
so ,we need to eliminate decimal from 0.9
as 0.9*10 = 9
thus,we multiply both 1.89 and 0.9 with 10, then we will have
(1.89*10) ÷ (0.9*10)
=> 18.9 ÷ 9
Thus, based on above calculation new look would be D. 18.9 ÷ 9
Answer:
I think it’s 22.50 not sure tho
Step-by-step explanation:
If 2 = $5 then u divide 5 by 2 to find the per cost and then multiply with 9 cakes
5/2 = 2.5(9) = 22.5
4/52 because 4 of each number and 52 total.
Answer:
$52.5 saved. And he paid $297.50
Step-by-step explanation:
First finding the amount of money of the 15% discount
350.00 × .15 = $52.5
Then the the original price minus the dicount
350.00 - 52.50 = $297.50
