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liubo4ka [24]
3 years ago
9

if 8 workers take 400 hours to finish a project how long will it take 16 workers to complete the same Project​

Mathematics
1 answer:
brilliants [131]3 years ago
5 0
The correct answer is 200 hours
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Is a/b +b/c rational number<br>​
Anarel [89]

Answer:

Yes.

Step-by-step explanation:

Yes.

Assuming a, b and c are integers (not = 0)

a/b + b/c

= (ac + b^2) / bc   which is a rational number.

3 0
2 years ago
Estimate the quotient to the nearest whole number by using compatible numbers 32.44 ÷ 4.36
GarryVolchara [31]
I'm pretty sure its 7
7 0
3 years ago
-112/3 x (-4 1/5) =?
TEA [102]

Answer:

sorry Wala po akong answer ehhh sorry

3 0
3 years ago
A recursive rule for a sequence is given. Find the first four terms of the sequence.
tigry1 [53]

Answer:  

So...

   a0 = -2

   a1 = (a0)2 - 4  =  4 - 4  =  0

   a2 = (a1)2 - 4 = ((a0)2-4)2 - 4 =...=  02 - 4  = -4  

       For an+1, you may use the previous term (an) if you have just calculated it, rather than calculating it recursively again

   a3 = (-4)2 - 4 = 12

 

The first four terms in the sequence are -2, 0, -4, 12.

Step-by-step explanation:

This recursive sequence is defined as follows:

 a0 = -2      [the first term]

 an+1 = an2 - 4     [for all other terms, n≥0; note that you cannot find a0 using this line]

 

Note that this is not "BASE" for a number base, but it is "SUB" for subscript, indicating the term.  Sometimes, sequences are written with the first term being a1 and sometimes sequences are written with the first term being a0.  This is because there are situations that make one or the other more convenient (for example, starting with elapsed time t=0 makes sense).

 

To find the value of later terms, a recursive definition requires that you find the value of the previous term, which requires that you find the value of the previous term, which requires that you find the value of the previous term, which requires that you find the value of the previous term, ... which requires that use the value of the first term.

 

That's why (joke) that the dictionary definition of "recursive" is "see recursive."

4 0
3 years ago
Let f(x)=x^2f ( x ) = x 2. Find the Riemann sum for ff on the interval [0,2][ 0 , 2 ], using 4 subintervals of equal width and t
sladkih [1.3K]

Answer:

A_L=1.75

Step-by-step explanation:

We are given:

f(x)=x^2

interval = [a,b] = [0,2]

Since n = 4 ⇒ \Delta x = \frac{b-a}{n} = \frac{2-0}{4}=\frac{1}{2}

Riemann sum is area under the function given. And it is asked to find Riemann sum for the left endpoint.

A_L= \sum\limits^{n}_{i=1}\Delta xf(x_i) = \frac{1}{2}(0^2+(\frac{1}{2})^2+1^2+(\frac{3}{2})^2)=\frac{7}{4}=1.75

Note:

If it will be asked to find right endpoint too,

A_R=\sum\limits^{n}_{i=1}\Delta xf(x_i) =\frac{1}{2}((\frac{1}{2})^2+1^2+(\frac{3}{2})^2+2^2)=\frac{15}{4}=3.75

The average of left and right endpoint Riemann sums will give approximate result of the area under f(x)=x^2 and it can be compared with the result of integral of the same function in the interval given.

So, (A_R+A_L)/2 = (1.75+3.75)/2=2.25

\int^2_0x^2dx=x^3/3|^2_0=8/3=2.67

Result are close but not same, since one is approximate and one is exact; however, by increasing sample rates (subintervals), closer result to the exact value can be found.

3 0
3 years ago
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