Answer:
4 times
Step-by-step explanation:
Sample space :
6 sided cube = (1, 2, 3, 4, 5, 6)
Coin = (H, T)
Probability = required outcome / Total possible outcomes
Probability of head (H) = P(H) = 1 /2 = 0.5
Probability of 3 = P(3) = 1 /6 = 0.166666
Probability of heads and 3 on a single try = p(H) * p(3) = 0.5 * 0.166666 = 0.083333
Hence, expected number of times this is likely to occur in 48 tries :
0.083333 * 48 = 4
Answer:
f(x)=cos(x)
The amplitude is equal to 1. The period is 2π.
Your thoughts are correct; Ned loses 14 points overall.
The reason the correctly answered questions do not factor into the answer is because that is not what the question is asking. Correct answers are not even mentioned :)
Since theres 4 numbers and 60 spins if you divide it you get the average number that all the numbers would land on. 2 would be landed on 15 times if it went exactly to the calculations. not 100% sure though
The answer is 15 to the question
