To put an equation into (x+c)^2, we need to see if the trinomial is a perfect square.
General form of a trinomial: ax^2+bx+c
If c is a perfect square, for example (1)^2=1, 2^2=4, that's a good indicator that it's a perfect square trinomial.
Here, it is, because 1 is a perfect square.
To ensure that it's a perfect square trinomial, let's look at b, which in this case is 2.
It has to be double what c is.
2 is the double of 1, therefore this is a perfect square trinomial.
Knowing this, we can easily put it into the form (x+c)^2.
And the answer is: (x+1)^2.
To do it the long way:
x^2+2x+1
Find 2 numbers that add to 2 and multiply to 1.
They are both 1.
x^2+x+x+1
x(x+1)+1(x+1)
Gather like terms
(x+1)(x+1)
or (x+1)^2.
Answer:
73.3
Step-by-step explanation:
7%=7÷100=0.07 ×60=4.2
15%=15÷100=0.15×60=9
add you answers to 60 and to should get 73.2
Answer:
Step-by-step explanation:
Given: 
Initial value: y(1)=6
Let 
Variable separable
Integrate both sides
Initial condition, y(1)=6
Put C into equation
Solution:
or
Hence, The solution is or
