Question

A right triangle has one leg that measures 7 inches and the hypotenuse measures 12 inches.

Answer 1

• Hypotenuse=H=12in
• Perpendicular=P=7in
• Base=B=?

Using Pythagorean theorem

$\boxed{\sf B^2=H^2-P^2}$

$\\ \sf \longmapsto \: b = \sqrt{ {h}^{2} - {p}^{2} } \\ \\ \sf \longmapsto \: b = \sqrt{ {12}^{2} - {7}^{2} } \\ \\ \sf \longmapsto \: b = \sqrt{100 - 49} \\ \\ \sf \longmapsto \: b = \sqrt{51} \\ \\ \sf \longmapsto \: b = 7.2in$