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Liono4ka [1.6K]
3 years ago
9

Which is the best estimate for written in scientific notation?

Mathematics
2 answers:
katen-ka-za [31]3 years ago
8 0

2.8 × 4.1 = 11.48

10³ × 10^{6}=10^{9}

11.48 x 10^{9}=1.2 x10^{10}

Drupady [299]3 years ago
7 0

For this case we have the following multiplication:

(2.8*10^3)(4.1*10^6)

We can rewrite the multiplication in the following way:

(2.8*4.1)(10^3*10^6)

Then, by properties of powers we have:

In the multiplication if we have the same base, the exponents are added:

(2.8*4.1)(10^{3+6})

Finally, we multiply both numbers in the parenthesis on the left and add the exponents in the parenthesis on the right:

(11.48)(10^{9})

Rewriting the result as scientific notation correctly, we have:

(1.2)(10^{10})

Answer:

The equivalent expression is given by:

(1.2)(10^{10})

option 1

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Answer:

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Step-by-step explanation:

To solve a non-factorable quadratic equation in the form of ax^2+bx+c=0, you need to use the quadratic formula where x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}:

3x^2+x-5=0

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x=\frac{-1\pm\sqrt{61}}{6}

Because of the \pm sign, quadratic equations always have two solutions, whether both are real, only one is real, or both are complex (in the form of a+bi where a is the real part and b is the imaginary part where i=\sqrt{-1}). In this case, because the discriminant is positive (defined as b^2-4ac), then there are 2 real solutions.

The solutions are thus x_1=\frac{1+\sqrt{61}}{6}\approx1.47,x_2=\frac{1-\sqrt{61}}{6}\approx-1.14

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