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taurus [48]
3 years ago
10

Suggest two reasons why the mass deposited was different from the expected value

Chemistry
1 answer:
asambeis [7]3 years ago
4 0

Answer:

1) Dissolution of the copper anode

2) Time of the reaction

Explanation:

The figure shows the electrolysis of Copper Chloride using copper electrodes.

In aqueous solution, the ions present in the solution include:  H⁺, OH⁻. Cu²⁺ Cl⁻

The half equations for the reaction  are:

At rhe Anode (positive electrode) : 2Cl⁻(aq) - 2e = Cl₂(g)

At the Cathode (negative electrode) Cu²⁺ (aq) + 2e = Cu (s)

Hence copper ions are reduced at the cathode by gaining two electrons to form copper solid deposits. It is the mass of the deposited copper that the student measured over time.

Reasons why the actual mass is different  from the expected mass

1) Dissolution of the copper Anode: The electrodes used for this experiment are copper electrodes as both the positive and negative electrode.

Under the influence of an electric current, the copper anode will dissolve by gaining electrons and go into solution as copper II ions (Cu²⁺). thereby increasing the amount of copper ions in solution.

The aqueous copper ions from the anode and from the copper chloride (CuCl₂ (aq) electrolyte will migrate to the negative cathode, gain electrons, and get deposited as pure copper solid.  This increases the mass of copper solid deposited at the cathode.

2) Time: As the time of the reaction from zero to sixty (60) minutes under the influence of an electric current, more of the copper anode will dissolve, migrate to the cathode and get deposited as copper solid.

Hence as the time of the reaction increases, more of the copper ions will be deposited as copper solid thereby increasing the value of the actual mass of copper deposited.

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A chemist added an excess of sodium sulfate to a solution of a soluble barium compound to precipitate all of the barium ions as
grigory [225]

Answer:

  259.497 mg,   58.84%

Explanation:

BaSO₄ → Ba²⁺ + SO₄²⁻

to calculate the mole of BaSO₄

mole BaSO₄ = mass given / molar mass = 403 mg / 233.38 g/mol = 1.7268 mol

comparing the mole ratio

1.7268 mol of BaSO₄ yields 1.7268 mol of Ba²⁺

403 mg BaSO₄  yields     ( 1.7268 × 137.327 ) where 137.327 is the molar mass of Barium mol of Ba²⁺

441 mg BaSO₄  will yield   ( 1.7268 × 137.327  × 441 mg ) / 403 mg = 259 .497 mg

mas percentage of the Barium compound = 259 .497 mg / 441 mg × 100 = 58.84%

8 0
3 years ago
Glucose, c 6 h 12 o 6 , is a good source of food energy. when it reacts with oxygen, carbon dioxide and water are formed. how ma
melomori [17]

94.0 L if the reaction takes place under STP.

<h3>Explanation</h3>

The molar mass of glucose C₆H₁₂O₆ is

12.01 × 6 + 1.008 × 12 + 16.00 × 16.00 = 180.16 g / mol.

126 grams of glucose will contain 126 / 180.16 = 0.69939 mol of C₆H₁₂O₆. (To avoid rounding errors, keep a couple more digits than necessary.)

6 moles of CO₂ will be produced when 1 mole of C₆H₁₂O₆ is consumed. 0.69939 moles of C₆H₁₂O₆ will give rise to 4.196 mol of CO₂.

Assuming that the reaction takes place under STP, where T = 0 °C = 273 K and P = 1 atm. Each mole of any ideal gas will occupy a volume of 22.4 liters. The 4.196 moles of CO₂ will occupy 4.196 × 22.4 = 94.0 L. (The least significant number given is 126 g, the mass of glucose. This number has three significant figures. Thus, round the result to three significant figures.)

The volume of CO₂ can be found using the ideal gas law if the condition isn't STP. For example, T = 25 °C = 297 K and P = 1.00 × 10⁵ will lead to a different volume. By the ideal gas law,

V = (n · R · T) / (P)

where

  • V is the volume of the gas,
  • n is the number of moles of gas particles,
  • R is the ideal gas constant<em>,</em>
  • P is the pressure on the gas,
  • T is the absolute temperature of the gas (in degrees Kelvin.)

R = 8.314 × 10³ L · Pa / (K · mol)

Taking T = 297 K and P = 1.00 × 10⁵ Pa,

V = (4.196 × 8.314 × 10³ × 297 ) / (1.00 × 10⁵ ) = 104 L.

3 0
3 years ago
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