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Dennis_Churaev [7]
3 years ago
12

What electrical charge does protons has

Chemistry
2 answers:
zalisa [80]3 years ago
8 0
Protons has "Positive" charge on them

Hope this helps!
Sveta_85 [38]3 years ago
7 0
If i am correct positive
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Give the correct number of significant figures in 1.900.0 kg*
elena-14-01-66 [18.8K]
1 significant figure
6 0
3 years ago
Student added a strip of aluminium metal in aqueous copper(2)Sulfate but no reaction occured. Suggest a reason why.
kari74 [83]

Answer:

See Explanation

Explanation:

It is a common observation that a strip of aluminium metal in aqueous copper(II)Sulfate does not show any visible reaction. Aluminium is normally expected to displace copper in solution since it is higher than copper in the electrochemical series.

The reason for this is that aluminium forms an oxide film around its surface which prevents reaction with aqueous copper(II)Sulfate. This oxides film protects the aluminium surface such that it is now unable to react with the aqueous copper(II)Sulfate

7 0
2 years ago
A newspaper story describing the local celebration of Mole Day on October 23 (selected for Avogadro's number, 6.02 X 10^ 23 ) at
stepladder [879]

Answer:

The answer is "670.176 km".

Explanation:

Volume of the occupies of one  M & M= 0.5 \ cm^3\\\\

M&M 1 mole= 6.02 \times 10^{23}\\\\

Calculating volume of M& M mole=  0.5 \ cm^3 \times 6.02 \times 10^{23}=3.01 \times 10^{23}\ cm^3\\\\

Calculating the cube moleL^3= 3.01 \times 10^{23}\ cm^3\\\\

L=6.70176 \times 10^{7}\ cm\\\\

   =6.70176 \times 10^{7}\ cm \times \frac{1\ m}{100\ cm}\\\\=670176\ m\\\\=670.176 \ km

Therefore 18 tractor trailers wouldn't be sufficient.

8 0
3 years ago
Calculate the molality for each of the following solutions. Then, calculate the freezing-point depression ΔTF = iKFcm produced b
zlopas [31]

Answer:

a) Cm= 3.9 m  ; ΔTf= 14.51 ºC

b) Cm= 0.21 m ; ΔTf= 0.79ºC

Explanation:

In order to solve the problems, we have to remember that the molality (m) of a solution is equal to moles of solute in 1 kg of solvent.

m= mol solute/kg solvent

a) In this case we have molarity, which is moles of solute in 1 liter of solution. We have to know how many kg of solvent (water) we have in 1 L of solution.

3.2 M NaCl= 3.2 mol NaCl/ 1 L solution

1 L solution= 1000 ml solution x 1.00 g/ml= 1000 g

A solution is composed by solute (NaCl) + solvent, so:

1000 g solution = g NaCl + g solvent

g NaCl= 3.2 mol NaCl x 58.44 g/mol= 187 g NaCl

g solvent= 1000 g - 187 g NaCl= 813 g= 0.813 kg

Cm= 3.2 g NaCl/0.813 kg solvent= 3.9 m

NaCl is an electrolyte and it dissociates in water in two ions: Na⁺ anc Cl⁻, si the van't Hoff factor (i) is 2.

ΔTf= i x KF x Cm= 2 x 1.86ºC/m x 3.9 m= 14.51ºC

b) In this case we have 24 g of solute in 1.5 L of solvent. We have to convert the liters of solvent to kg, and to convert the mass of solute to mol by using the molecular weight of KCl (74.55 g/mol):

24 g KCl x 1 mol KCl/74.55 g= 0.32 mol

1.5 L solvent= 1500 g solvent x 1.00 g/ml= 1500 g = 1.5 kg

Cm= 0.32 g KCl/1.5 kg solvent= 0.21 m

KCl is an electrolyte and when it dissolves in water, it dissociates in 2 ions: K⁺ and Cl⁻. For this, van't Hoff factor (i) is equal to 2.

ΔTf= i x KF x Cm= 2 x 1.86ºC x 0.21 m= 0.79ºC

7 0
3 years ago
When dissolved in water, a neutral molecule of calcium chloride dissociates into three ions - one calcium ion and two chloride i
Mashcka [7]

Explanation:

Calcium chloride is an ionic compound as it is formed by transfer of an electron to each chlorine atom.

So, being an ionic compound calcium chloride is able to dissociate completely into water.

Hence, the dissociation reaction will be as follows.

         CaCl_{2}(s) \rightarrow Ca^{2+}(aq) + 2Cl^{-}(aq)

Since, two electrons has been lost by single calcium atom. Therefore, calcium atom will have a charge of +2.

Thus, we can conclude that the charge on the calcium ion, in elementary units is +2.

8 0
2 years ago
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