Answer:
So, The possible values of h and r are
1. r = 3 , h = 3
2. r = 1, h = 27
3. r = 2, h = 6.75
Step-by-step explanation:
P.S - The exact ques is -
As we know that Volume of cone , V = 
As given,
V = 
⇒
So,
The possible values of h and r are
1. r = 3 , h = 3
2. r = 1, h = 27
3. r = 2, h = 6.75
In Case I-
When r = 3, h = 3
(3)² ×3 = 9×3 = 27
Satisfied
Case II-
r = 1, h = 27
(1)²×27 = 1×27 = 27
Satisfied
Case III-
r = 2, h = 6.75
(2)²×6.75 = 4×6.75 = 27
Satisfied
Answer:
The velocity of the car after the collision is -5.36 m/s
Step-by-step explanation:
An elastic collision is an encounter between two bodies in which the total kinetic energy of the two bodies remains the same.
let the following:
m₁ = mass of the car = 1400 kg
m₂ = mass of the truck = 3200 kg
u₁ = velocity of the car before collision = 13.7 m/s
u₂ = velocity of the truck before collision = 0 m/s
v₁ = velocity of the car after collision
v₂ = velocity of the truck after collision
v₁ = [ u₁ * (m₁ - m₂) + u₂ * 2m₂ ]/ (m₁ + m₂)
= [ 13.7 * (1400 - 3200) + 0 * 2 * 3200 ]/ (1400 + 3200)
= - 5.36 m/s
So, <u>the velocity of the car after the collision is -5.36 m/s</u>
Answer:
answer is below
Step-by-step explanation:
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