Answer:
- False
- False
- True
Step-by-step explanation:
Since the given expression represents the account balance, the initial amount (when x=0) is $500 in Account A, and $100 in Account B. (Less money was invested in account B.)
The growth rate of each account is $1.03 per year.* (The growth rate ($/year) is identical for each account.)
The total of the initial amounts invested is $500 +100 = $600.
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<em>* Comment on growth rate</em>
Since the account balance is shown as <em>greater than</em> or equal to the given expression, there appears to be the possibility that adjustments are made to the account balance by some means other than the growth predicted by this inequality. For example, if the balance in Account A is $900 at the end of 1 year, the inequality will still be true, but the extra $398.97 will be in addition to the $1.03 growth predicted by this expression.
This means <em>we really cannot say what the growth rates of the accounts might be</em>, except that it is a minimum of $1.03 per year in each account.
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<em>Comment on the expressions</em>
More usually, we would expect to see an account balance have the equation a = 400·1.03^x. That is, the interest rate would be 3% and it would be compounded annually. The expression 400 + 1.03x is very unusual in this situation.
