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3 years ago

6

PLEASE HELP ME AND BE CORRECT BEFORE ANSWERING

1 answer:

Rudiy273 years ago

4 0

A translation by 3 units down and 1 unit to the left

Hope this helps! Please make me the brainliest, it’s not necessary but appreciated, I put a lot of effort and research into my answers. Have a good day, stay safe and stay healthy.

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The length of a rectangle is three centimeters less than the width. If one area of the rectangle is 53 cm^2, find the dimensions

andreev551 [17]

A= Area
l= length
w= width

l= w-3cm
A= l*w
A= 53cm²
53= l*w
(plug in value of length)
53= (w-3)(w)
0=w²-3w+53
Use the quadratic formula:
(in the pictures attached)
w= about 9cm
l=9-3= 6cm

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3 years ago

The rectangle below has an area of x^2 - 9 square meters and a width of x - 3 meters.

Rama09 [41]

Answer:

x+3

Step-by-step explanation:

Area of a rectangle is $L\cdot W$ .

We know the width, W, is $x-3$ and we know the area is $x^2-9$ .

Inputting this in our formula above we get:

$x^2-9=L(x-3)$

L is a an expression such that when you multiply it to $(x-3)$ gives you $(x^2-9)$ .

$x^2-9$ is a difference of squares and can be factored using:

$a^2-b^2=(a-b)(a+b)$ .

$x^2-9=(x-3)(x+3)$ .

So L=x-3 and W=x+3.

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3 years ago

the bottom of a vase is a square.each side measury y+11 units.the square has a perimeter of 55 units what is the value of y?

Norma-Jean [14]

Answer:

2.75

Step-by-step explanation:

55-11(4)=2.75

2.75+11=13.75

13.75x4=55

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