Answer:
<h2>
∠PQT = 72°</h2>
Step-by-step explanation:
According to the diagram shown, ∠OPQ = ∠OQP = 18°. If PQT is a tangent to the circle, it can be inferred that line OQ is perpendicular to line QT. Ths shows that ∠OQT = 90°.
Also from the diagram, ∠OQP + ∠PQT = ∠OQT;
∠PQT = ∠OQT - ∠OQP
Given ∠OQP = 18° and ∠OQT = 90°
∠PQT = 90°-18°
∠PQT = 72°
The length of ladder is 30 ft.
<h3>How can the feet that made up the side of the building is the top of the ladder be known ?</h3>
The formula below can be used in solving the problem
Tan (∅)= 
∅=70°
opposite = BC
Adjacent = 12 ft
70°= opposite/ 12
opposite= 32.96 ft
Therefore, The length of ladder is 30 ft.
NOTE; Since the actual diagram can not be found i solved another on on the same topic
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CHECK COMPLETE QUESTION BELOW:
Consider the diagram shown where a ladder is leaning against the side of a building. the base of the ladder is 12ft from the building. how long is the ladder? (to the nearest ft)
a. 25ft
b. 30ft
c. 35ft
d. 40ft
Answer:
the slope is stepper and the line is shifted up
Answer:
The scale is not reasonable.
Step-by-step explanation:
The painting is 48 inches by 120 inches
The scale is 1 inch = 4 inches
Divide the painting size by 4
48/4 = 12 inches
120/4 = 30 inches
We would need paper that is
12 inches by 30 inches
Our paper is 12 inches by 24 inches
It is too small. The scale is not reasonable