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Lilit [14]
2 years ago
7

Plssss help i need to have this problem done by today or else my dad will be mad at me.

Mathematics
1 answer:
antoniya [11.8K]2 years ago
4 0

Answer:

x is 24° it is bcs triangle have at all 180°

that bigger one have 180-94-41=45° on right side

180-111-45=24° ez

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HELP PLEASE!!
cestrela7 [59]

Answer:

Quadrilateral FSHB∼quadrilateral KTWJ.

Step-by-step explanation:

Given two quadrilaterals we have to prove these two similar.

The two quadrilaterals are similar if the corresponding sides of these are proportional then only the quadrilateral are proportional i.e

∴ \frac{FS}{KT}=\frac{SH}{TW}=\frac{HB}{WJ}=\frac{BF}{JK}

If the above condition satisfied then the quadrilateral are similar.

Let us find these ratios

\frac{FS}{KT}=\frac{28}{21}=1.333

\frac{SH}{TW}=\frac{24}{18}=1.333

\frac{HB}{WJ}=\frac{18}{13.5}1.333

\frac{BF}{JK}=\frac{18}{13.5}1.333

All ratios are equal.

Hence, the corresponding sides and angles of these two quadrilaterals are proportional implies that these two are similar i.e quadrilateral FSHB∼quadrilateral KTWJ.




7 0
3 years ago
Read 2 more answers
The box plots show the weights, in pounds, of the dogs in two different animal shelters. Weights of Dogs in Shelter A 2 box plot
katovenus [111]

Answer:

1) The median weight for shelter A is greater than that for shelter B.

True, the median weight for shelter A is 21 pounds as compared to the 18 pounds median weight for shelter B.

4) The data for shelter B are a symmetric data set.

True, the median is exactly 2 pounds away from each quartile which means it is symmetric.

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

True, the interquartile range of shelter A is 11 pounds as compared to the 4 pounds interquartile range of shelter B.

Step-by-step explanation:

We are given two box-plots, a box plot basically shows 5 statistical characteristics of a data set and they are  

1. minimum value  

2. Lower quartile  

3. Median value  

4. Upper quartile  

5. Maximum value  

Box-plot of dogs in shelter A:

The whiskers range from 8 to 30

Which means that the range is = 30 - 8 = 22

The box ranges from 17 to 28

Which means that the interquartile range is = 28 - 17 = 11

21 - 17 = 4

28 - 21 = 9

The median is not equal distance away from each quartile which means that the box-plot is not symmetric.

A line divides the box at 21

Which means that the median is = 21

Box-plot of dogs in shelter B:

The whiskers range from 10 to 28

Which means that the range is = 28 - 10 = 20

The box ranges from 16 to 20

Which means that the interquartile range is = 20 - 16 = 4

18 - 16 = 2

20 - 18 = 2

The median is exactly 2 pounds away from each quartile which means it is symmetric.

A line divides the box at 18

Which means that the median is = 18

Which is true of the data in the box plots?

1) The median weight for shelter A is greater than that for shelter B.

True, the median weight for shelter A is 21 pounds as compared to the 18 pounds median weight for shelter B.

2) The median weight for shelter B is greater than that for shelter A.

False

3) The data for shelter A are a symmetric data set.

False

4) The data for shelter B are a symmetric data set.

True

5) The interquartile range of shelter A is greater than the interquartile range of shelter B.

True, the interquartile range of shelter A is 11 pounds as compared to the 4 pounds interquartile range of shelter B.

5 0
3 years ago
The figure shows the location of a golf ball after a tee shot. How many feet from the hole is the ball?
bixtya [17]

Answer:

Il ressemble à 3 pieds

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Y=(1/2)^x +2. What is the horizontal asymptote of this function?
professor190 [17]
\lim_{x\to -\infty} \left(\frac{1}{2}\right)^x+2=\infty+2=\infty\\
\lim_{x\to \infty} \left(\frac{1}{2}\right)^x+2=0+2=2\\

There is one-sided horizontal asymptote y=2
6 0
3 years ago
Hey can someone help me?
RoseWind [281]
No sir .it’s 100 +18
4 0
2 years ago
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