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3 years ago

PLZ HELPPPPPP

Mathematics

2 answers:

PilotLPTM [1.2K]3 years ago

5 0

Answer: Reflection across the y axis.

Clockwise rotation

Step-by-step explanation:

d1i1m1o1n [39]3 years ago

5 0

Answer:

The sequence of transformations that can be performed on quadrilateral ABCD to show that it is congruent to quadrilateral GHIJ is a 90-degree counterclockwise rotation about point A followed by a reflection across the y-axis and a translation 20 units down .

Step-by-step explanation:

You might be interested in

Determine the equation of the line that is perpendicular to the lines r(t)=(-2+3t,2t,3t)

Mnenie [13.5K]

Vector Equation
(Line)(x,y) = (x,y) + t(a,b);tERParametric Formx = x + t(a), y = y + t(b); tERr = (-4,-2) + t((-3,5);tERFind the vector equation of the line passing through A(-4,-2) & parallel to m = (-3,5)Point: (2,5)
Create a direction vector: AB = (-1 - 2, 4 - 5)
= (-3,-1) or (3,1)when -1 (or any scalar multiple) is divided out.
r = (2,5) + t(-3,-1);tERFind the vector equation of the line passing through A(2,5) & B(-1,4)x = 4 - 3t
y = -2 + 5t
;tERWrite the parametric equations of the line passing through the line passing through the point A(4,-2) & with a direction vector of m =(-3,5)Create Vector Equation first:
AB = (2,8)
Point: (4,-3)
r = (4,-3) + (2,8); tER
x = 4 + 2t
y = -3 + 8t
;tERWrite the parametric equations of the line through A(4,-3) & B(6,5)Make parametric equations:
x = 5 + 4t
y = -2 + 3t ; tER
For x sub in -3
-3 = 5 + 4t
(-8 - 5)/4 = t
-2 = t
For y sub in -8
-8 = -2 + 3t
(-8 + 2)/3 = t
-2 = t
Parameter 't' is consistent so pt(-3,-8) is on the line.Given the equation r = (5,-2) + t(4,3);tER, is (-3,-8) on the line?Make parametric equations:
x = 5 + 4t
y = -2 + 3t ; tER
For x sub in 1
-1 = 5 + 4t
(-1 - 5)/4 = t
-1 = t
For y sub in -7
-7 = -2 + 3t
(-7 + 2)/3 = t
-5/3 = t
Parameter 't' is inconsistent so pt(1,-7) is not on the line.Given the equation r = (5,-2) + t(4,3);tER, is (1,-7) on the line?Use parametric equations when generating points:
x = 5 + 4t
y = -2 + 3t ;tER
X-int:
sub in y = 0
0 = -2 + 3t
solve for t
2/3 = t (this is the parameter that will generate the x-int)
Sub t = 2/3 into x = 5 + 4t
x = 5 + 4(2/3)
x = 5 + (8/3)
x = 15/3 + (8/3)
x = 23/3
The x-int is (23/3, 0)What is the x-int of the line r = (5,-2) + t(4,3); tER?Note: if they define the same line: 1) Are their direction vectors scalar multiples? 2) Check the point of one equation in the other equation (LS = RS if point is subbed in)What are the two requirements for 2 lines to define the same line?

3 0

4 years ago

Find the value of x of this

almond37 [142]

x: 93⁰ × 117⁰ × 87⁰ x⁰ ×

x : x

3 0

3 years ago

The y intercept of a function is where x = 0 True False

natka813 [3]

The answer is true :)

6 0

3 years ago

(50 points and brainliest.Need help ASAP)

Aleksandr-060686 [28]

Answer: " 2x (2x - 1) (x + 1) " .

______________________________________

Step-by-step explanation:

______________________________________

Given:

f(x) = 9x³ + 2x² − 5x + 4 ;

g(x) = 5x³ − 7x + 4 ;

______________________________________

What is: f(x) − g(x) ?

______________________________________

Plug in: " 9x³ + 2x² − 5x + 4 " for: " f(x) " ;

and: " (5x³ − 7x + 4) " ; for: "g(x)" ;

______________________________________

→ " f(x) − g(x) =

" 9x³ + 2x² − 5x + 4 − (5x³ − 7x + 4) " .

______________________________________

Rewrite this expression as:

→ " 9x³ + 2x² − 5x + 4 − 1(5x³ − 7x + 4) " .

→ {since: " 1 " ; multiplied by "any value" ; is equal to that same value.}.

______________________________________

Now, let us example the following portion of the expression:

______________________________________

" − 1(5x³ − 7x + 4) "

_____________________________________

Note the "distributive property" of multiplication:

______________________________________

→ a(b + c) = ab + ac ;

______________________________________

Likewise:

→ a(b + c + d) = ab + ac + ad .

______________________________________

As such:

______________________________________

→ " − 1(5x³ − 7x + 4) " ;

______________________________________

= (-1 * 5x³) + (-1 * 7x) + (-1 * 4) ;

= - 5x³ + (-7x) + (-4) ;

= - 5x³ − 7x − 4 ;

_____________________________________

Now, add the "beginning portion of the expression" ; that is:

" f(x) " ; to the expression ; which is:

→ 9x³ + 2x² − 5x + 4 ;

→ as follows:

_______________________________________

→ 9x³ + 2x² − 5x + 4 − 5x³ − 7x − 4 ;

→ {Note that the: " - " sign; that is;

the "negative sign", in the term: " -5x³ " ;

becomes a: " − " sign; that is; a "minus sign" .}.

______________________________________

Now, combine the "like terms" of this expression; as follows:

+ 9x³ − 5x³ = + 4x³ ;

− 5x − 7x = − 2x ;

+ 4 − 4 = 0 ;

______________________________________

and we have:

______________________________________

→ " 4x³ + 2x² − 2x ".

______________________________________

Now, to write this answer in "factored form" :

Note that among all 3 (three) terms in this expression, each term has a factor of "2" . The lowest coefficient among these 3 (three) terms is "2" ; so we can "factor out" a "2".

Also, each of the 3 (three) terms in this fraction is a coefficient to a variable. That variable takes the form of "x". The term in this expression with the variable, "x"; with the lowest degree has the variable: "x" (i.e. "x¹ = x" ) ; so we can "factor out a "2x" (rather than just the number, "2".).

So, by factoring out a "2x" ; take the first term [among the 3 (three) terms in the expression] —which is: "4x³ " .

2x * (?) = 4x³ ? ;'

↔ $\frac{4x^3}{2x} =$ ? ;

→ 4/2 = 2 ;

$\frac{x^{3}}{x} = \frac{x^3}{x^1} = x^{(3-1)} = x^{2}$ ;

As such: 2x * (2x²) = 4x³ ;

___________________________________________

Now, by factoring out a "2x" ; take the second term [among the 3 (three) terms in the expression] — which is: "2x² " .

2x * (?) = 2x² ? ;

↔ $\frac{2x^{2}}{2x} =$ ?

→ 2/2 = 1 ;

→ $\frac{x^{2}}{x} = \frac{x^2}{x^1}= x^{(2-1)} } = x^1 = x$ ;

As such: 2x * (x) = 2x²

__________________________________________

Now, by factoring out a "2x" ; take the third term [among the 3 (three) terms in the expression] — which is: " − 2x " .

2x * (?) = - 2x ;

↔ $\frac{-2x}{2x} =$ -1 ;

As such: 2x * (-1) = − 2x .

__________________________________________

So:

__________________________________________

Given the simplified expression:

→ " 4x³ + 2x² − 2x " ;

We can "factor out' a: " 2x " ; and write the this answer is: "factored form" ; as:

__________________________________________

"2x (2x² + x − 1 ) . "

Now, we can further factor the:

" (2x² + x − 1) " ; portion;

Note: "(2x² + x - 1)" =

2x² + 2x - 1x -1 = (2x -1) + x (2x - 1 ) =

(2x - 1) ( x + 1)

_______________________________________

Now, bring down the "2x" ; and write the Full "factored form" ; as follows:

_______________________________________

→ " 2x (2x - 1) (x + 1) " .

_______________________________________

Hope this helps!

Wishing you the best!

_______________________________________

7 0

3 years ago

......,................

dem82 [27]

Answer:

Step-by-step explanation:

Given

4n² + 4(4m³ + 4n² ) ← distribute terms in parenthesis by 4

= 4n² + 16m³ + 16n² ← collect like terms

= (4n² + 16n²) + 16m³

= 20n² + 16m³

= 16m³ + 20n² ← in standard form → A

3 0

3 years ago