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KengaRu [80]
3 years ago
7

Help me with this question...

Mathematics
1 answer:
eimsori [14]3 years ago
3 0

Answer:

Option D

Step-by-step explanation:

Since, \frac{x-y}{x+y}=\frac{2}{7}

7(x - y) = 2(x + y)

7x - 7y = 2x + 2y

7x - 2x = 2y + 7y

5x = 9y

\frac{x}{y}=\frac{9}{5}

Since, ΔAED is similar to ΔACB,

Corresponding sides of these triangles will be proportional.

\frac{BC}{DE}=\frac{AC}{AE}

\frac{x}{y}=\frac{8+AE}{AE}

\frac{9}{5} =\frac{8+AE}{AE}

9(AE) = 40 + 5AE

9(AE) - 5(AE) = 40

4(AE) = 40

AE = 10 cm

Therefore, Option D will be the answer.

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The equation of the hyperbola in standard form is \frac{(y-4)^{2}}{100}-\frac{(x-1)^{2}}{64}=1

Step-by-step explanation:

Let us revise the equation of the hyperbola

The standard form of the equation of a hyperbola with  center (h , k) and transverse axis parallel to the y-axis is  \frac{(y-k)^{2}}{a^{2}}-\frac{(x-h)^{2}}{b^{2}}=1

  • The length of the transverse axis is 2a  
  • The length of the conjugate axis is 2b  

∵ The center of the hyperbola is (1 , 4)

∴ h = 1 and k = 4

∵ The transverse axis is parallel to the y-axis

∴ The form of the equation is  \frac{(y-k)^{2}}{a^{2}}-\frac{(x-h)^{2}}{b^{2}}=1

∴ The length of the transverse axis is 2a  

∵ The length of the transverse axis is 20 units

- Equate 2a by 20 to find a

∴ 2a = 20

- Divide both sides by 2

∴ a = 10

∵ The length of the conjugate axis is 2b

∵ The length of the conjugate axis is 16

- Equate 2b by 16 to find b

∴ 2b = 16

- Divide both sides by 2

∴ b = 8

- Substitute the values of h, k, a, and b in the form of the equation

∴  \frac{(y-4)^{2}}{(10)^{2}}-\frac{(x-1)^{2}}{(8)^{2}}=1

∴  \frac{(y-4)^{2}}{100}-\frac{(x-1)^{2}}{64}=1

The equation of the hyperbola in standard form is \frac{(y-4)^{2}}{100}-\frac{(x-1)^{2}}{64}=1

Learn more:

You can learn more about the hyperbola in brainly.com/question/4054269

#LearnwithBrainly

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