-20 15 degrees colder -20-15=

nadya68 [22]

For a relation to be called a function, it must pas the vertical line test and each x-value must have a unique y-value

<span>The graph of this sequence would pass the vertical line test.
</span>Each day corresponds to a unique amount of pennies in this sequence.

8 0

3 years ago

Read 2 more answers

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

So

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

So

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

7 0

3 years ago

You are given 3 to 1 odds against tossing three tails with three coins, meaning you win $3 if you succeed and you lose $1 if

valentina_108 [34]

Step-by-step explanation:

To find the E(X) expected value, you come up with the different probabilities for each outcome
your set of outcomes after 3 tosses would be = {HHH, HHT, HTH, THH, HTT, THT, TTH, TTT} where H is heads and T is tails
Each element has a probability of 1/8 so let x represent number of tails
$Probability(x)=P(x)\\P(0)=\frac{1}{8} \\P(1)=\frac{3}{8} \\P(2)=\frac{3}{8} \\P(3)=\frac{1}{8}$
The E(x)=Summation (x times P(x))
$E(X)=(0)(0.125)+(1)(0.375)+(2)(0.375)+(3)(0.125)=1.5$
Now which probability is 1.5 tails? None, so it is either 2 tails or 1 tails
So you can expect to lose money in 1 game
But as you play more games the probability of getting 3 tails becomes more and more likely, so you can expect to win in a 100 games

8 0

3 years ago

Find the mode for a data set. 18,24,24,24,25,37,37,46

Sphinxa [80]

Answer:

24 is the mode

Step-by-step explanation:

Mode is the number that is most often seen.

18 is seen 1 time

24 is seen 3 times

25 is seen 1 time

37 is seen 2 times

46 is seen 1 time

24 is the mode because it is seen the most often.

4 0

3 years ago

Read 2 more answers

9(9h + 4b + 9), for h = 7 and b = 3<br><br> Evaluate

irakobra [83]

So, when adding in the 7 and 3 the new equation is:
9{(9x7)+(4x3)+9}

Following pemdas, you have to do parenthesis first. So now the equation is:
9(63+12+9)

Now distribute the 9:

567 + 108 + 81

And finally solve as a normal addition problem:

567 + 108 + 81= 756

So, the answer is 756.

I hope this helps:)

6 0

3 years ago