We know that
<span>This problem can be represented through the following equation
</span>
A = A₀(1/2)^t/h
where
A-----------> is the amount of substance left after time t
A₀ ----------> is the original amount---------> 2 g
h-------------> is the half-life-----------> 8 days
for A=0.04 g
t=?
0.04 = 2(1/2)^t/8
0.02 = (1/2)^t/8
Take ln on both sides:
ln(0.02) = ln [(1/2)^t/8]
ln(0.02) = (t/8)(ln 1/2)
t = 8*ln(0.02)/ln(1/2)
t = 45.15 days
the answer is 45.15 days
0.2(3) reoccurring.
Easiest way I can think of is to just put it in to a calculator and convert to a fraction, haha. Have fun counting up reoccurring numbers manually.
The answer is
Answer:
D. 264yards
Step-by-step explanation:
If John swam halfway across a circular pond (radius) and he has gone 132 yds, then the radius of the circular pond is 132yards.
Diameter of the pond = 2×radius of the pond
Diameter of the pond = 2×132
Diameter of the pond = 264yards
Answer: 125%
Step-by-step explanation: 20/20 is 100%, 5 is 25% of 20, or 1/4. So add 25 to 100 and its 125
Answer:
15 and 17 are both undefined, 16 the slope is 0
Step-by-step explanation: