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AfilCa [17]
3 years ago
15

Help please it's due 11:59 pm

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0

They would work harder at A because if they sell 3 cars they would get paid more than if they worked at B

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Zielflug [23.3K]

To be clear, the given relation between time and female population is an integral:<span>
</span>t = \int { \frac{P+S}{P[(r - 1)P - S]} } \,&#10;dP<span>

</span>

<span>The problem says that r = 1.2 and S = 400, therefore substituting:<span>
</span>t = \int { \frac{P+400}{P[(1.2 - 1)P - 400]}&#10;} \, dP<span>

</span>= <span><span>&#10;\int { \frac{P+400}{P(0.2P - 400)} } \, dP

In order to evaluate this integral, we need to write this rational function in a simpler way:
</span>\frac{P+400}{P(0.2P - 400)} = \frac{A}{P} +&#10;\frac{B}{(0.2P - 400)}</span><span>

</span>where we need to evaluate A and B. In order to do so, let's calculate the LCD:<span>
</span>\frac{P+400}{P(0.2P - 400)} = \frac{A(0.2P -&#10;400)}{P(0.2P - 400)} + \frac{BP}{P(0.2P - 400)}<span>

</span>the denominators cancel out and we get:<span>
</span>P + 400 = 0.2AP - 400A + BP<span>
</span>             = P(0.2A + B) - 400A<span>

</span>The two sides must be equal to each other, bringing the system:<span>
</span>\left \{ {{0.2A + B = 1} \atop {-400A =&#10;400}} \right.<span>

</span>Which can be easily solved:<span>
</span>\left \{ {{B=1.2} \atop {A=-1}} \right.<span>

</span>Therefore, our integral can be written as:<span>
</span>t = \int { \frac{P+400}{P(0.2P - 400)} } \,&#10;dP = \int {( \frac{-1}{P} + \frac{1.2}{0.2P-400} )} \, dP<span>
</span>= - \int { \frac{1}{P} \, dP +&#10;1.2\int { \frac{1}{0.2P-400} } \, dP<span>
</span>= - \int { \frac{1}{P} \, dP +&#10;6\int { \frac{0.2}{0.2P-400} } \, dP<span>
</span>= - ln |P| + 6 ln |0.2P - 400| + C<span>

</span>Now, let’s evaluate C by considering that at t = 0 P = 10000:<span>
</span>0 = - ln |10000| + 6 ln |0.2(10000) - <span>400| + C
C = ln |10000</span>| - 6 ln |1600|<span>
</span>C = ln (10⁴) - 6 ln (2⁶·5²)<span>
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</span></span><span><span> </span>Therefore, the equation relating female population with time requested is:<span>
</span><span>t =  - ln |P| + 6 ln |0.2P - 400| + 4 ln (10) - 36 ln </span>(2) - 12 ln (5)</span></span>
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Step-by-step explanation:

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