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Tom [10]
3 years ago
9

The table above lists the frequencies of the C major key.

Mathematics
1 answer:
Talja [164]3 years ago
7 0
Sj ebfbruejnxjjendnzjejnzzkijeskao
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2/5 as a whole number
ANTONII [103]
.4 is your answer....................                                                                       
5 0
3 years ago
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Please help i need an A
Basile [38]

Answer:

(1) 820

(2) 1920

Step-by-step explanation:

(1) solving 20 x 41, using associative property.

20 * 41  = (2 x 10) x 41  = 2 x (10 x 41)

             = 20 x 41         = 2 x 410

             = 820              =  820

(2) distribute 32 as 30 + 2 and solve.

     60 x 32

  = 60 x (30 + 2) = 60(30) + 60(2)

                        = 1800 + 120

                        = 1920

             

3 0
3 years ago
1. Flight 202's arrival time is normally distributed with a mean arrival time of 4:30
Bezzdna [24]

Answer:

Step-by-step explanation:

1) Let the random time variable, X = 45min; mean, ∪ = 30min; standard deviation, α = 15min

By comparing P(0 ≤ Z ≤ 30)

P(Z ≤ X - ∪/α) = P(Z ≤ 45 - 30/15) = P( Z ≤ 1)

Using Table

P(0 ≤ Z ≤ 1) = 0.3413

P(Z > 1) = (0.5 - 0.3413) = 0.1537

∴ P(Z > 45) = 0.1537

2)  By compering (0 ≤ Z ≤ 15) ( that is 4:15pm)

P(Z ≤ 15 - 30/15) = P(Z ≤ -1)

Using Table

P(-1 ≤ Z ≤ 0) = 0.3413

P(Z < 1) = (0.5 - 0.3413) = 0.1587

∴ P(Z < 15) = 0.1587

3) By comparing P(0 ≤ Z ≤ 60) (that is for 5:00pm)

P(Z ≤ 60 - 30/15) = P(Z ≤ 2)

Using Table

P(0 ≤ Z ≤ 1) = 0.4772

P(Z > 1) = (0.5 - 0.4772) = 0.0228

∴ P(Z > 60) = 0.0228

6 0
3 years ago
Answer The Questions
lana66690 [7]

Answer:

Step-by-step explanation:

That’s easy

5 0
2 years ago
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10^6 in standard form
nalin [4]
1000000 is the answer
6 0
3 years ago
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