Answer:
Height of the square pyramid is 6.569 centimeter
Step-by-step explanation:
The volume of the square pyramid is 94.5 cubic centimeters
The height of the square pyramid will be equal to the lengths of the sides of the square.
The volume of the square pyramid is given by

or
centimeter
Height of the square pyramid is 6.569 centimeter
Answer:
116
Step-by-step explanation:
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Answer:
A
Step-by-step explanation:
Construct a perpendicular bisector of segment AB.
Perpendicular bisector is a line that divides the line into two equal halves forming 90° at the intersection point.
So, points A and B will be at the same distance from the intersection point.
If the constructed line (perpendicular bisector) is the reflection axis, then point B will be the refection point of A.
Answer:
The given point is a solution to the given system of inequalities.
Step-by-step explanation:
Again, we can substitute the coordinates of the given point into the system of inequalities. We know that the x-coordinate and y-coordinate of
are
and
, respectively.
Plugging these values into the first inequality,
, gives us
, which simplifies to
. This is a true statement, so the given point satisfies the first inequality. We still need to check if it satisfies the second inequality though, because if it doesn't, it won't be a solution to the system.
Plugging the coordinates into the second inequality,
, gives us
, which simplifies to
. This is also a true statement, so the given point satisfies the second inequality as well. Therefore,
is a solution to the given system of inequalities since it satisfies all of the inequalities in the system. Hope this helps!

Recall that

Take it one piece at a time. For

, we can scale

by -5:

If we shift the argument by 1 and scale by -5, we have

so if we subtract this from

, we'll end up with

For the next piece, we can add another scaled and shifted step like

so that

For the last piece, we add one more term:

and so putting everything together, we get

:
