Answer:
<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>
Step-by-step explanation:
Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units
From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.
By the definition of rhombus, diagonals meet at right angles.
Implies that PQ = QA
x+2 = 3x - 14
x-3x=-14-2
-2x=-16
2x = 16
dividing by 2 on both sides, we will get,

<h3>∴ x=8</h3><h3>Since Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles we can equate x+2 = 3x-14 to find the value of x.</h3>
The line segment 


( since x=8)


<h3>∴

units</h3>
<span>LJK = KJM
-10x +3 = -x + 21
-10x + x = 21 - 3
-9x = 18
x = -2
KJM = -x + 21 = 2 + 21 = 23
LJM = LJK + KJM
LJM = 23 + 23
LJM = 46º..
i think thats how its done </span>
A=1/2ap
(40ft^2)=1/2*8*p
p=(40ft^2)/4
2/5, 1/10, and 1/20 are all less than 1/2
Measure of z is 116°.The measure of y is 48°.Hope this helps.