Answer:
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Step-by-step explanation:
Calculation for the equation that can be
use to find the maximum and minimum times for the track team
Using this equation to find the maximum times for the track team
T maximum=T average -7.8 seconds
T maximum=64.6 seconds-7.8 seconds
Using this equation to find the minimum times for the the track team
T minimum=T average +7.8 seconds
T minimum=64.6 seconds +7.8 seconds
Therefore the equation for the maximum and minimum times for the track team are :
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Answer:
6
Step-by-step explanation:
To solve this , we use the equation of finding a slope wig a line.
m = (y2 - y1)/(x2 - x1)
From the question, we know that:
y2 = y
x2 = 3
y1 = 2
x1 = 1
m = 2
Hence,
2= (y - 2)/(3 - 1)
2 = (y - 2)/2
4 = y - 2
y = 2 + 4 = 6
Answer:
20.485 Meters
Step-by-step explanation:
So first you wanna draw a diagram. Start with the tower, then on the ground to the left (or right) draw a point. The point will be labeled as 42 m away from the tower. Now draw a line from that point to the top of the tower. This makes your triangle, and that angle you just drew that touches the point is 26 degrees.
Now, since you have a right triangle you can use trig. You know an angle and a side. Specifically, relative to the 26 degree angle you know the adjacent angle and want the opposite, which is the tower. So opposite and adjacent is tangent. So you set up tan(26) = o/42 where o is the opposite side.
So solving you get o = 20.485 meters
True because log times A and B will also be logA and Log B
Answer:
0.0009
Step-by-step explanation:
