If 12 was added to one-third of a certain number to get 35. What is this number? *
1 answer:
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X^2+16-38=0
find what 2 numbers multiply to get -38 and add to get 16
find factors of 38
2 times 19
there is no way to use common factor so use quadratic formula which is
x=
or x=
ax^2+bx+c=0 subsitte
a=1
b=16
c=-38
subsitute
=
= 
= 
=
so the answers for x are and 
which are aprox -2.099504938362 and +18.099504938362
so it would be
(x-[-8+√102])(x+[8+√102])=0
find what 2 numbers multiply to get -38 and add to get 16
find factors of 38
2 times 19
there is no way to use common factor so use quadratic formula which is
x=
ax^2+bx+c=0 subsitte
a=1
b=16
c=-38
subsitute
so the answers for x are
so it would be
(x-[-8+√102])(x+[8+√102])=0