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Stolb23 [73]
3 years ago
11

What table of values goes with the equation y = l-2x l?

Mathematics
1 answer:
Sergio [31]3 years ago
6 0

x, y

0, 0

1, 2

2, 4

3, 6

4, 8

etc.

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

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kondor19780726 [428]

Answer:

He said he accidentally sent this so I just want everyone who reads this to have a good rest of their day:)

Step-by-step explanation:

5 0
3 years ago
The owner of a furniture store decides to reduce the price of a sofa from $800 to $560. By what percentage was the price of the
KIM [24]

The percentage that the store has taken off would be 30%.

5 0
3 years ago
Two houses on the same side of the street have house numbers that are consecutive
DochEvi [55]

Answer:

28 and 30

Step-by-step explanation:

'x' = 1st consecutive #

'x+2' = 2nd consecutive #

x + x+2 = 58

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3 0
2 years ago
Find the exact value of sin(cos^-1(4/5))
boyakko [2]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2762144

_______________


Let  \mathsf{\theta=cos^{-1}\!\left(\dfrac{4}{5}\right).}


\mathsf{0\le \theta\le\pi,}  because that is the range of the inverse cosine funcition.


Also,

\mathsf{cos\,\theta=cos\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]}\\\\\\
\mathsf{cos\,\theta=\dfrac{4}{5}}\\\\\\ \mathsf{5\,cos\,\theta=4}


Square both sides and apply the fundamental trigonometric identity:

\mathsf{(5\,cos\,\theta)^2=4^2}\\\\
\mathsf{5^2\,cos^2\,\theta=4^2}\\\\
\mathsf{25\,cos^2\,\theta=16\qquad\qquad(but,~cos^2\,\theta=1-sin^2\,\theta)}\\\\
\mathsf{25\cdot (1-sin^2\,\theta)=16}

\mathsf{25-25\,sin^2\,\theta=16}\\\\
\mathsf{25-16=25\,sin^2\,\theta}\\\\
\mathsf{9=25\,sin^2\,\theta}\\\\
\mathsf{sin^2\,\theta=\dfrac{9}{25}}


\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{9}{25}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\sqrt{\dfrac{3^2}{5^2}}}\\\\\\
\mathsf{sin\,\theta=\pm\,\dfrac{3}{5}}


But \mathsf{0\le \theta\le\pi,} which means \theta lies either in the 1st or the 2nd quadrant. So \mathsf{sin\,\theta} is a positive number:

\mathsf{sin\,\theta=\dfrac{3}{5}}\\\\\\
\therefore~~\mathsf{sin\!\left[cos^{-1}\!\left(\dfrac{4}{5}\right)\right]=\dfrac{3}{5}\qquad\quad\checkmark}


I hope this helps. =)


Tags:  <em>inverse trigonometric function cosine sine cos sin trig trigonometry</em>

3 0
3 years ago
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Please help with 7-11
Thepotemich [5.8K]
The answer there is,-4
7 0
3 years ago
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