How do you write 5y-9=0 in standard form?
1 answer:
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<h3>Answer 1a :- </h3>
Here we can solve this question using<em> </em><em>Unitary</em><em> </em><em>Method</em><em> </em><em>.</em> As ;
→ In 17hrs the boat travels 452km
→ In 1hr the boat will travel 452km/17
→ In 9hrs the boat will travel 452/17km * 9 = 239.29km
→ A car can travel 156km on 13L gasoline .
→ It will travel 1km on 13/156L of gasoline .
→ It will travel 480km on 13/156*480L = 40L of gasoline .
→ A boat can go 180 miles on 60L gasoline.
→ It will go 1mile in 60/180L of gasoline.
→ It will go 306 miles in 60/180*306L = 102L of gasoline .
→ On 51L of gasoline a car can go 408km
→ On 1L of gasoline car will go 408/51 km
→ On 11L of gasoline it will go 408/51*11L = 88km