In a cookie jar containing 6 chocolate chip cookies, 8 sugar cookies, and 10 peanut butter cookies, what is the probability that
1 answer:
Hello there.
Question: I<span>n a cookie jar containing 6 chocolate chip cookies, 8 sugar cookies, and 10 peanut butter cookies, what is the probability that a person who isn’t looking as they pull out one cookie, will get a chocolate chip cookie?
Answer: First you need to calculate the total of cookies in the jar.
6 + 10 + 8 = 24.
There are 6 chocolate chip cookies.
Therefore the fraction is </span>
You can simplify it after that if you wish to.
In short, Your answer is .
In simplified form it would be
.
Hope This Helps You!
Good Luck Studying ^-^
Question: I<span>n a cookie jar containing 6 chocolate chip cookies, 8 sugar cookies, and 10 peanut butter cookies, what is the probability that a person who isn’t looking as they pull out one cookie, will get a chocolate chip cookie?
Answer: First you need to calculate the total of cookies in the jar.
6 + 10 + 8 = 24.
There are 6 chocolate chip cookies.
Therefore the fraction is </span>
You can simplify it after that if you wish to.
In short, Your answer is
In simplified form it would be
Hope This Helps You!
Good Luck Studying ^-^
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Answer:
(18, 14)
Step-by-step explanation:
We know that C and D lie on the line AB and BC = CD = AB. Then we need to use the distance formula and equation of the line AB to find the other two coordinates.
The distance formula states that the distance between two points and
, the distance is denoted by:
. Let's find the distance between A and B:
d =
Now say the coordinates of D are (a, b). Then the distance between D and B will be twice of 2√13, which is 4√13:
4√13 =
Square both sides:
208 = (6 - a)² + (6 - b)²
Let's also find the equation of the line AB. The y-intercept we know is 2, so in y = mx + b, b = 2. The slope is (6 - 2) / (6 - 0) = 4/6 = 2/3. So the equation of the line is: y = (2/3)x + 2. Since (a, b) lines on this line, we can put in a for x and b for y: b = (2/3)a + 2. Substitute this expression in for b in the previous equation:
208 = (6 - a)² + (6 - b)²
208 = (6 - a)² + (6 - (2/3a + 2))² = (6 - a)² + (-2/3a + 4)²
208 = a² - 12a + 36 + 4/9a² - 16/3a + 16 = 13/9a² - 52/3a + 52
0 = 13/9a² - 52/3a - 156
13a² - 156a - 1404 = 0
a² - 12a - 108 = 0
(a + 6)(a - 18) = 0
a = -6 or a = 18
We know a can't be negative so a = 18. Plug this back in to find b:
b = 2/3a + 2 = (2/3) * 18 + 2 = 12 + 2 = 14
So point D has coordinates (18, 14).