When two lines are <em><u>parallel, that means they have the same slope! </u></em>
The slope is the coefficient of x
In the equation y = 3x, <u>the slope is 3 </u>
An example of a line that is above y = 3x is ...
y = 3x + 2
The "+2" <em>shifts the line up </em>by 2 on the y axis
An examples of a line that is below y = 3x is ...
y = 3x - 3
The "-3" <em>shifts the line down</em> by 3 on the y axis
We have to simplify
sec(θ) sin(θ) cot(θ)
Now first of all let's simplify these separately , using reciprocal identities.
Sec(θ) = 1/cos(θ)
Sin(θ) is already simplified
Cot(θ)= cos(θ) / sin(θ) ,
Let's plug these values in the expression
sec(θ) sin(θ) cot(θ)
= ( 1/cos(θ) ) * ( sin(θ) ) * ( cos(θ) / sin(θ) )
= ( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
sin cancels out with sin and cos cancels out with cos
So , answer comes out to be
=( sin(θ) /cos(θ) ) * ( cos(θ) /sin(θ) )
= 1
Answer:
256 total
Step-by-step explanation:
112 boys
144 girls
Answer:
Well the whole answer is 10.246950 smth smth but I don’t have the multiple choices so your gonna have to round yourself
Step-by-step explanation:
Okay so you have a weigh of 8 and a diagonal of 13.
If you look, theres a triangle there. One side has 8 and the diagonal that was cut forms a 13. So we have a leg and a hypotnuse. To find the other leg (length) just follow the Pythagorean theroum and solve for b or a.
Pythagorean theroum: a^2+b^2=c^2
Now subsitute c for 13 since its the hypotnuse and a or b as 8 but only one.
In this case I’m substituting a for 8.
8^2+b^2=13^2
Solve the squares
64+b^2= 169
Isolate the b
b^2=105
Now square root 105
√105 will give the answer above on a normal calculator but if you have to round, I don’t know what place but you can round.
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