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Lubov Fominskaja [6]
3 years ago
8

Azul spun a tri-color spinner twice. What is the probability that the spinner landed on the colors blue and green in any order?

BB, BG, BY, GB, GG, GY, YB, YG, YY 2 ON 3 Acvate Win Gettings to​
Mathematics
1 answer:
guapka [62]3 years ago
8 0

Answer:

The Probability that the spinner landed on the colors blue and green in any order = 2/9

Step-by-step explanation:

Given - Azul spun a tri-color spinner twice.

To find - What is the probability that the spinner landed on the colors blue and green in any order?

Solution -

Given that,

A tri-color spinner spun twice

So,

The Sample Space, S = {BB, BG, BY, GB, GG, GY, YB, YG, YY}

⇒n(S) = 9

Now,

Let A be an event that the spinner landed on the colors blue and green

So,

A = {BG, GB}

⇒n(A) = 2

Now,

Probability that the spinner landed on the colors blue and green in any order = n(A) ÷ n(S)

         = 2 ÷ 9

∴ we get

The Probability that the spinner landed on the colors blue and green in any order = 2/9

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madreJ [45]

Answer:

95 times

Step-by-step explanation:

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So no. of times 5 is expected when the number cube is rolled out 570 times = 570*1/6 = 95 times

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Step-by-step explanation:

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7x+3=24 what is the value of 5-4x
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Makenzie is looking to purchase a used Jeep Wrangler that costs $21,000. She will make a $4,000 down payment and borrow the rema
olga_2 [115]

Answer:

$323

Step-by-step explanation:

The monthly payment can be calculated using the formula:

M=\frac{P(\frac{r}{12})(1+\frac{r}{12})^n}{(1+\frac{1}{12})^n-1}\\\\

where:

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Our parameters are defined as:

n=60\\P=21000-4000=17000\\r=5.3%\\\\

We plug our parameters in the equation to solve for M;

M=M=\frac{P(\frac{0.053}{12})(1+\frac{0.053}{12})^n}{(1+\frac{0.053}{12})^{60}-1}\\\\\\\\

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Answer:

Option B.

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So, the vertices of image are G'(3,2), F'(1,4) and H'(-1,1).

Therefore, the correct option is B.

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