So since the vertex falls onto the axis of symmetry, we can just solve for that to get the x-coordinate of both equations. The equation for the axis of symmetry is , with b = x coefficient and a = x^2 coefficient. Our equations can be solved as such:
y = 2x^2 − 4x + 12:
y = 4x^2 + 8x + 3:
In short, the vertex x-coordinate's of y = 2x^2 − 4x + 12 is 1 while the vertex's x-coordinate of y = 4x^2 + 8x + 3 is -1.
Answer:
not factorable
Step-by-step explanation:
The easiest way to factor is to find two numbers of the "a" value (the coefficient before ) and the factors of the c value (10) that ADD up to give you -9, in this case it would be:
1 -10 --> 1(-10) gives you -10
1 -1 --> 1(-1) gives you -1
adding these together -10 + (-1) = -11 which does not equal -9.
You could stop here and conclude that this is not factorable by inspection.
Another method: using the quadratic formula to find its roots.
Roots: and