What is the domain of the function y=sqrt x+6-7

1 answer:

8 0

Answer:

$x \geqslant 1$

Step-by-step explanation:

$\sqrt{x + 6 - 7} = \sqrt{x - 1} \\ \\ x - 1 \geqslant 0 \\ x \geqslant 1$

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