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postnew [5]
3 years ago
9

someone pls help me :Jada and her sister went to the store together. After the store, Jada walked 9 blocks west to get a coffee

and her sister walked 6 blocks west back to work. How many blocks is the coffee shop that Jada went to from her sister's work?
Mathematics
2 answers:
Musya8 [376]3 years ago
3 0

Answer:

3 blocks away from Jada's sister's work.

Nikolay [14]3 years ago
3 0

Answer:

3 blocks

Step-by-step explanation:

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Work out 25% of 20 metres
Bumek [7]
<span>25% of 20 meters
</span>25%=1/4 so 1/4 of 20 is 5 meters


6 0
3 years ago
Read 2 more answers
Pleaseeee helppp answer correctly !!!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!
Tanya [424]

Answer:

⦣ACD = 90º

Step-by-step explanation:

⦣ACD + ⦣BCD = 180º

⦣BCD = 90º

⦣ACD + 90º = 180º                 subtract 90º from both sides

⦣ACD = 90º

3 0
3 years ago
The contents of a sample of 26 cans of beer showed a standard deviation of 0.06 ounce. We are interested in testing to determine
snow_tiger [21]

Answer:

The null hypothesis should not be rejected.

Step-by-step explanation:

We are given that the contents of a sample of 26 cans of beer showed a standard deviation of 0.06 ounce.

Let \sigma^{2} = <u><em>population variance</em></u>

So, Null Hypothesis, H_0 : \sigma^{2} \leq 0.003      {means that the variance of the population is significantly less than or equal to 0.003}

Alternate Hypothesis, H_A : \sigma^{2} > 0.003      {means that the variance of the population is significantly more than 0.003}

The test statistics that would be used here <u>One-sample chi-square</u> test statistics;

                           T.S. =  \frac{(n-1)\times s^{2} }{\sigma^{2} }  ~  \chi^{2}__n_-_1

where, s^{2} = sample variance = 0.06^{2} = 0.0036 ounces

            n = sample of cans of beer = 26

So, <u><em>the test statistics</em></u>  =  \frac{(26-1)\times 0.0036 }{0.003 }  ~ \chi^{2}__2_5

                                     =  30

The value of chi-square test statistics is 30.

Since in the question, we are not given with the level of significance so we assume it to be 5%. <u>Now at 5% level of significance, the ch-square table gives a critical value of 37.65 for right-tailed test.</u>

Since our test statistics is less than the critical value of chi as 30 < 37.65, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the variance of the population is significantly less than or equal to 0.003.

8 0
3 years ago
Help(T_T)<br> "Give 7.897 correct to 2 decimal places"
Lynna [10]

Answer:

7.89 till two decimal places.....

hope it helps

7 0
2 years ago
If x= -1 and y = -21, then xy – 5x =
aev [14]

Answer:

a i think

Step-by-step explanation:

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