The function has a slope : m = - 2 and contains the point ( 8, 12 ).
y = m x + b
12 = ( - 2 ) * 8 + b
12 = - 16 + b
b = 12 + 16
b = 28
The slope-intercept form of the function is:
y = - 2 x + 28
Answer:
M = 4.33885225095
Step-by-step explanation:
Area of the square ABFE = 10² = 100
M = 100 - (2P + Q)
Let’s calculate 2P + Q :
The area 2P + Q = area ΔABC + area of sector ACE + area of sector BCF
Note :
ΔABC is an equilateral triangle
m∠CBF = m∠CAE = 30°
area ΔABC = (CG × AB)÷2 = (8.660254037844×10)÷2 = 43.30127018922
CG = √(10^2 - 5^2)=8.660254037844 (Pythagorean theorem)
area of sector BCF = area ΔACE = 100π ÷ 12 = (8.333333333333)π
then
Area 2P + Q = area ΔABC + area sector ACE + area sector BCF
= 43.30127018922+(100÷12)π+(100÷12)π
= 43.30127018922+ (8.333333333333)π + (8.333333333333)π
= 95.66114774905
Conclusion:
M = 100 - (2P + Q) = 100-95.66114774905 = 4.33885225095
Answer:

Step-by-step explanation:
Given equation of line:

To find the equation of line perpendicular to the line of the given equation and passes through point (8,2).
Applying slope relationship between perpendicular lines.

where
and
are slopes of perpendicular lines.
For the given equation in the form
the slope
can be found by comparing
with standard form.
∴ 
Thus slope of line perpendicular to this line
would be given as:

∴ 
The line passes through point (8,2)
Using point slope form:

Where
and 
So,

Using distribution.


Adding 2 to both sides.


Thus the equation of line in standard form is given by:

Answer:

Step-by-step explanation:
Consecutive angles of a parallelogram are are supplementay.
